Greetings to all.     How to calculate the differential in hardware needs (a radiator size and coolant mass and ...) ?

A plain simple automobile uses a number of litres of water as coolant on a radiator of such and such dimensions.  If the water specific heat capacity is 4,181 J/kg°C , a very high number compared to many other fluids- is replaced by plain motor oil / transmission fluid; what does it translate to ?  --> Doubling the area/volume/fanning of its radiator ? Tripling ? 

As replacement of water based coolant in ICE engines, transmission fluid can:
- Eliminate rust progress or prevent it,
- Eliminate boiling at operating temperatures,
- Eliminate pressurized circuits,
- Eliminate specialized orange, green, whatever coolants,
- Increase efficiency with hotter combustion if wanted by thermostat choice,
- Even used transmission oil at $0 is good enough,
- Better heat transfer wettability
- No more blown head gaskets perhaps ?

- No freezing at comparable temperatures...

Are these above correct ?  Is there more ?

 

 

The heat capacity of oil (engine oil) is about half that of water, so you need to pump roughly twice the flow rate.
To a first approximation I don't think it would need a different size radiator, but you would need much more pressure to pump a more viscous material at a higher flow rate.
I think you would need to redesign the engine block with bigger cooling passages and either run a bigger pump (which would also need cooling) or use a bigger radiator with bigger "holes".


Good luck convincing anyone it's worth trying.