DimaMazin Posted December 19, 2018 Share Posted December 19, 2018 (edited) Let's consider unit circle with central point x=0 ;y=0 a is an angle in rad x is cosine of angle a y is sine of angle a Area of tryangle is At=y*x/2 Area of segment a = a/2 Area of half of sector 2a =area of segment of a - area of tryangle = a/2 - yx/2= a - y(1-y2)1/2 Can area of half of sector 2a be calculated by integration if x=31/2/2 then x2=1 (3^1/2)/2f1 (1 - x2)1/2 dx How to calculate the integral? Edited December 19, 2018 by DimaMazin Link to comment Share on other sites More sharing options...
John Cuthber Posted December 19, 2018 Share Posted December 19, 2018 I suspect you will get more help if you draw a diagram. Link to comment Share on other sites More sharing options...
DimaMazin Posted December 20, 2018 Author Share Posted December 20, 2018 7 hours ago, John Cuthber said: I suspect you will get more help if you draw a diagram. Link to comment Share on other sites More sharing options...
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