pulkit

Ah' date=' speaking of trig,

 

sin c * cos c = -.5

 

Is it possible to find out c?[/quote']

 

Multiply equation by 2 to get Sin 2c = -1

Then you can use standard results to get your set of solutions

To pulkit' date=' the volume does not increase, is that because that the solute is completely dissolved in the solvent? and according to YT2095, the voleme does increase, is that because the solute is not completely dissolved in the solvent?

 

Albert[/quote']

 

To make my point clear, I was trying to say that delta V of solution is not zero in general. Even if you mix a cc of E1 with b cc of E2, you might and up with something less than a+b cc or something less than a+b cc. Both cases are quite common. Solution formations for which enthalpy change is negative, also have a negative delta V, and conversely positive enthalpy change is generally accompanied with positive delta V.

wow ! thats quite a lot cheaper.

Let them get that cheap over here, and I'll surely buy one.

still fairly new to linux, desktop is quite "empty"

Volumes are not necessarily additive during mixing ! Keep that in mind before manipulating the volume of solute and/or solvent.

Any changes on mixing aare neglected because in most cases, they are too small to bother us.

How much does a DVD-R/RW drive cost ?

Last I checked around these parts it was $120.

well, how low is hydroflouric on the Ph scale? i saw it on www.power-labs.com[/url'], it ate through a glass vile in under a minute, and would tear your hand off pretty fast.

pH is good for comparison, under a particular concentration. You should look at degree of dissociation, which for HF is quite low. It might dissolve glass but it is a weak acid. Weaker than HCl and much much weaker than HI.

Even if the body is 70% water (I did have that in mind while making my earlier posts), the extremely large molecules found else where might still compensate for that. As far as my interpretation of a mole is concerned, you can express as avg molecular weight of a human the total mass / total moles of molecules constituting. Its a defination thats worthless as far as reaching any numerical value is concerned, but seems to be conceptually alright to me.

The actual energy of formation of most molecules in the body may not be known, they are generally too complex and occur in too little an amount for any such analysis. It does seem to be an easy problem with any obvious intuitive solutions.

P(A)=4/7

P(B)=2/7

P©=1/7

Since the game goes on till someone wins, your sample space is infinite {H,TH,TTH,TTTH,TTTTH,.......}

Result is found by summing an infinite GP

constant you are lookign for = 10^{-14}

wtf is alien'sblood ?

Given that you want to talk in KCal/mol, it would be just a weighted average of all the molecules present in the body. Since many of these are really big, the number I would imagine might be close to 10,000 or 100,000 KCal/mol

It depends totally on which concept of acid-base do you use.

The H and OH ion is the Arrhenius concept of acid and bases.

You also have the Bronstead concept.

But the most general one is the Lewis concept. It can explain how chemicals with no H such as SbF5 and AlCl3 are acidic in nature.

pH below 0 and above 14 are not nice things and most often you do not deal with such solutions.

In most cases, the pH values between 0 and 14 suffice for all sane discussions about solutions/acids/bases/buffers etc..

It does not actually have attraction for oil.

Polar head is hydrophillic and non polar head is hydrophobic.

The hydrophobic heads move towards oil or grease only to avoid water.

Benzene and acetic acid won't react if you simply mix them.

Talking about clarity..........can you explain the clarity using only the information about the structure at the atomic level ?

Silicon dioxide isn't bonded with two double covalent bonds' date=' why?

Silicon dioxide has four single covalent bond instead?

Why it can't form that?[/quote']

 

You can generally explain choice of bond formation based on energy considerations. In most probability, energy considerations will explain this too.

"Argon is only known to participate in inter-stitial compounds. It is not involving any chemical change but only a physical change as far as compound formation is concerned. Helium does not form anything. Xenon that way is very nice because of its stable flourides."

 

Summary: Only noble gases that can form a compound with another element are krypton and xenon... ?

Yes. Atleast those are the only ones for whom compounds have been synthesized till now. Maybe someone will someday come up with compounds for the other too.

As far as Radon is concerned, its size is favourable to compound formation, though due to its radioactivity, I don't think too many people have tried to make compounds with it. Atleast I have never heard of a Radon compound.

When you have to deal with mod, the methid metioned is the most convenient to use.

Is there a simple way to create such beautiful gif images of logical circuits ?

I'd surely like to know.

Was this for me it seems like it is but it may be a general response. I just ask as I don't want to be ignorant and I had an experience where I was asked questions in a board I forgot I posted on.

Partially yes.

I meant to say that you could reduce it two input simple gates like AND,OR and XOR.

No fancy stuff.

I am in my second year doing a BS in comp science as well.

We are doing similar stuff. A pretty bad function I must say, no real simplification is possible.

As far as implementing using two input gates, that is always possible, but your drawing would then become too complicated. There is an easy way to go from n input to 2 input.

PS : By this time I realise there is absolutely nothing that YT has not done.

You only reject answers when the equations you started with were not simple quadratics. In such cases you have no choice but to follow this check, accept or reject approach.

I am talking purely from the point of view of solving the problem.

Of course I know energy is always conserved. But, you only find that to be useful for elastic collisions. For inelastic ones, you only end up with an extra unknown ,i.e. , heat disipated. Even knowing thermodynamic properties of matter will not help, you MUST know coefficient of restitution to get vel of sep = e * vel of approach.

In the first one use the formula for Sin(a)-Sin(b) , you will end up with a term Sin(x) upon x which in the limit will turn out to be one. Note that youĺl need to put 1/2 = Sin (pi/6)