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Fuzzwood

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Posts posted by Fuzzwood

  1. I too am interested in this (the soda lime is no where near basic enough to abstract a proton from toluene, unless I am mistaken?). Although not the requested, mechanism, here's one I had from a while back. IIRC, the double bond and the "six-membered" intermediate are a couple of things to look for; they make the reaction take place under much milder conditions (nevermind, in this case, the re-aromatization driving the thing). I think it may be relevant.

     

    For other examples of this sort of thing, check out the Strecker degradation whereby, in the presence of a reducing sugar (50 g/100 or so) amino acids are decarboxylated to yield the aldehyde, ammonia and CO2. For example, phenylalanine yields phenylacetaldehyde. The reaction proceeds first via the Schiff base with the carbohydrate. See also Maillard reaction and Amadori rearrangement. I have made this reaction work at 80°C.

     

    Cheers,

     

    O3

     

    Nono, its oxidized to benzoic acid first (potassium permanganate is a good option), THEN decarboxylize it.

  2. I personally find this opinion quite intriguing. We, indeed, are running out of room on this planet. A little extra space would do us good. But I think there are better funds to pull out of, such as solving cancer. A cure has already been found people, it's just not allowed out there by the government because of all the money they are raking in from cancer treatments, medicines, donations ect.

     

    Proof? Or is this just a complot theory?

  3. Basically, what Bascule said. Learned motor skiils (e.g. playing a guitar, riding a bike, driving a car etc.) are known as automaticities. These are ballistic patterns of motor function that are cpontrolled by the cerebellum and, once initiated, can be carried out to completion without any conscious input from the individual. Conscious input is only required to modulate the action.

     

    SNIP

     

    Even better, the moment you actually start thinking about those actions, you dont know what you need to do anymore

  4. The additional 4000 µg of lead added to half of the original sample caused a raise of 32 mV. Considering you used only half of the sample, that means you started with 62.5 mV. This means; 4000 µg of lead is the equivalent of 94.5 mV (157 - 125/2). Dividing those gives the response of the detector: 4000/94.5 = 42.4 µg of lead/mV

     

    As the sample gave a signal of 125 mV, this means there was 42.4 * 125 = 5291 µg of lead in the swabs.

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