bloodhound

in the bible there is a hidden code that says the world ends at 2006 , according to some random documentary.

isnt anti freeze like poisonous.

huh. u forgot to attach something. for me.... just check the avatar

general or the special? i also dont know what they state. is it something along the lines of speed of light being the same in all frames

like i said. He's located in Kathmandu, Nepal. where piracy is at all time high so even ig he DID buy it. its highly likely that he bought a pirated copy... with a blacklisted key.

problem with hollywood is that they spend MASSIVE money on film, so then HAVE to follow a set formula to make the film a sure fire hit, which results in many being cliched and highly unartistic.

Asian filmmakers dont have that problem

phi for all goes wild

turns haiku into random

Po-em , suc--suck it.

well, any sort of rule , "law" would be welcome then

hmm. we havent had a problem with avast yet. using it on two computers at home.... i like the boot scan thingy.(scans computer before windows loads up)

So even after I explicitly show you an infinite well ordered set (as a collection of rational s yuo deny such a thing is possible? Wow, you are blind.

Did u read his last post? he just have you an example of an infinite well ordered set

"A model of one of them in the reals would be

[math]\{1/2,2/3,4/5,5/6,...\} \cup \{3/2\}[/math]"

i ve heard some good things about f secure. but i right now am going russky with kaspersky

i am not familiar with it. googled it. couldnt understand it. how widely is it used?

any physicsy threorem would be welcome... so would some chemistry biology. ...

go for the DVD uncut edition of "Once upon a time in america" its really good like i said before. Very impressive cast. altough there is a quite violent rape scene.

ill nominate chain rule. makes life easier .

Chain rule

Let [math]f\colon ]a,b[ \to \mathbb{R}[/math] and [math]f'(x) [/math] exist. Let [math]g[/math] be defined on the image of [math]f[/math] and differentiable at [math]f(x)[/math]. Then the composite function [math]G\colon ]a,b[ \to \mathbb{R}[/math] given by

[math]G(y)=g\circ f(y)=g(f(y))[/math] for all [math]y \in ]a,b[[/math], is differentiable at x and

[math]G'(x)=g'(f(x))f'(x)[/math]

quite a nice result.

I think ill allow the natural selection, altough not technically a theorem , everyones heard of it, and probably quoted it once in a while

bought norton? i doubt it. piracy was on a record high when i last went to kathmandu. most likely it was a pirated copy with a pirated key, and norton has long blacklisted the key.

Norton was good a while back ago, but with each release it just takes over ur computer more and more. Altough i got nothing againts norton. There are better antivirus solutions as well as being free. Download the avast home edition which is free. it has a very good track record.

This week we are rewarding the What People Think is The Most Used Theorem In the Whole Of Physics, Chemistry, Biology and obviously Mathematics.

Place your nominations NOW!!!. voting will commence on 1st of January!!

Current Nominees:-

1)Pythagoras's Theorem

2)Fundamental Theorem of Calculus

3)Chain Rule

Note: natural selection removed due to the fact that its not a theorem and general displeasure among the formites. If you want it back, you will have to put up a strong case for it

 

If both discontinuous functions between [math]\mathbb{R}[/math] members (which are not 0 or 1) and 0 and 1 are defined' date=' then the collection of [math']\mathbb{R}[/math] members between 0 and 1 is a finite collection.

it seems that with each new post you introduce terms that highly unorthodox.

you can find many discontinuous functions in the interval [0,1]

the most famous being

[math]\chi \colon [0,1] \to \{0,1\}[/math] where

[math]\chi(x)=0[/math] if x is rational, and

[math]\chi(x)=1[/math] if x is irrattional.

Do u still contend that [0,1] is a finite collection?

[altough i do not understand what the existance of the discontinuous function has to do with anything at all]

Recommendation: Look up Cantor's Diagonal Arguement.

bit embarassing to say that I honestly dont know much about how pi is used in trigonometry.

offtopic: i just found out that doron and matt have a long history at physicsforum... just wondering what happened? did he get banned from there?

Intelligent and Sophisticated People listen to Intellingent and Sophisticated Genres like Jazz and Classical .. w00t

that probably cos u will just get [math]\pi[/math] instead of the number ur looking for

u still havent replied to my last question. I havent officially studied "well ordered set" but have only a vague notion of it. so i can't give u an example.

If you mean to the set which is based on [0' date=1] then if 0 and 1 are included in the set then this set has finitely many elements, because in any case that the maximum an the minimum are in the set, then there is a diccontinuous function between any arbitrary member, which is not 0 or 1 (in this case) and 0 or 1, and the rusult is a set with finitely many elements.

I got no idea what this paragraph says..

"A discontinuous function between any arbitary member"? what is that? once you explained what it is, i would like to see the proof of existance.