frankenstein18 Posted November 15, 2015 Share Posted November 15, 2015 I'm studying Sn2 reactions and I know that Iodine is a weaker base and therefore a better leaving group than Br In an exercise in my book (essential organic chem 3rd edition by paula yurkanis bruice) it asks to see which is more reactive between 1-bromo-2 phenylethane and 1-iodo-2 phenylethane1-bromo-2 phenylethane and 1-iodo-2 phenylethane look pretty much the same except that one has Br and the other has IodineI thought it was 1-iodo-2 phenylethane because it has a better leaving group but the back of the book says its 1-bromo-2 phenylethaneDoes the book have an error or am I just not understanding? Link to comment Share on other sites More sharing options...
hypervalent_iodine Posted November 15, 2015 Share Posted November 15, 2015 Does it offer an explanation? Could you post the question as it appears in the book? I would have picked the iodo compound as well. Link to comment Share on other sites More sharing options...
John Cuthber Posted November 15, 2015 Share Posted November 15, 2015 (edited) I would also have picked the iodinated version as more reactive. And, for what it is worth, Hypervalent Iodine and I are both chemists. Edited November 15, 2015 by John Cuthber Link to comment Share on other sites More sharing options...
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