muskan Posted April 17, 2017 Share Posted April 17, 2017 A vessel of mass 80 g(S. H. C. = 0.8 J/g) contains 250 g of water at 35°C. Calculate the amount of ice at 0°C, which must be added to it, so that the final temperature is 5°C. ( Latent heat of ice = 340 J/g). Link to comment Share on other sites More sharing options...
Sriman Dutta Posted April 17, 2017 Share Posted April 17, 2017 What have you done so far??? Link to comment Share on other sites More sharing options...
muskan Posted April 20, 2017 Author Share Posted April 20, 2017 first we need to convert ice to water. then, can we use the first law of thermodynamics here? Link to comment Share on other sites More sharing options...
swansont Posted April 20, 2017 Share Posted April 20, 2017 You need an equation that gives the energy required in this conversion of ice to water, and to changes in temperature of water. Link to comment Share on other sites More sharing options...
strachanbrad Posted April 22, 2017 Share Posted April 22, 2017 (edited) You have to start by finding out the amount of energy (latent heat (of fusion in this case)) 'Q' to melt the ice Q=MLf then add that to the amount of energy required to raise the the temp from 0 - 5 degrees Q=MCΔT. Add the Q's together. then use that amount to find the mass of ice Edited April 22, 2017 by strachanbrad Link to comment Share on other sites More sharing options...
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