Domagoj Posted February 28, 2016 Share Posted February 28, 2016 Look just at position 1. We have work done from left to right p1A1d1, and work done from right to left p2A2d2. What will happen if pressure p2 is higher than pressure p1, but A1d1 is bigger than A2d2, and lets say they result with a net work = 0 Link to comment Share on other sites More sharing options...
swansont Posted February 28, 2016 Share Posted February 28, 2016 What equations apply to this situation? Link to comment Share on other sites More sharing options...
Domagoj Posted February 28, 2016 Author Share Posted February 28, 2016 I am really not expert at this, but hope this can help you A1v1 = A2v2 Net work done on the system = p1A1d1 - p2A2d2 the volumes A1d1 and A2d2 must be equal. Denote their volumes by V i.e. V = p1A1 = p2A2 The mass m of the fluid in sections A1d1 and A2d2 is given by ρV where ρ is the density of the fluid. Thus p1A1 = p2A2 = m/ρ Consequently, Link to comment Share on other sites More sharing options...
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