Domagoj

I am really not expert at this, but hope this can help you A1v1 = A2v2 Net work done on the system = p1A1d1 - p2A2d2 the volumes A1d1 and A2d2 must be equal. Denote their volumes by V i.e. V = p1A1 = p2A2 The mass m of the fluid in sections A1d1 and A2d2 is given by ρV where ρ is the density of the fluid. Thus p1A1 = p2A2 = m/ρ Consequently,

Look just at position 1. We have work done from left to right p1A1d1, and work done from right to left p2A2d2. What will happen if pressure p2 is higher than pressure p1, but A1d1 is bigger than A2d2, and lets say they result with a net work = 0

Yeah i know it is a very simple question but i was not familiar with those terms energy and hidraulic grade line, i thought there is something more here than simple logic.

I m not an expert in these things so correct me if I m wrong..Head is the height of the water in a Tank... Does head loss mean that that height is lowered so that Tank in the bottom of the hill can have water in it, without the water being spilled out of the bottom tank. lets say the tanks are open and water can go out Look at this drawing (dont mind the text in the picture)...Is it possible that water stays that way and doesnt go out through the lower tank

Bottom of tank 1 is above the top of tank 2. Outlet is going from the bottom of tank 1, diagonaly to the bottom of tank 2. The thing I want to find out....is there a way for those two Tanks to be connected so they are both full... Is that even possible and I would like if someone can explain what exactly head loss mean and is it connected with my problem.

If we have 2 Tanks. Tank 1 is on the hill, and Tank 2 is on the bottom of the hill. They are connected, is it possible that whole water doesnt go to the Tank 2. And can someone explain to me hydraulic grade line, head loss, and energy line.