So i'm stuck on a tutorial I've been sent to do, could anyone help me out please?

 

i have no idea where to start, I've looked through all my previous lecture notes but i can't find a logical way to solve the problems.

 

i've attached the tutorial.

 

Thanks.

After breaking my neck reading the scrolls you posted i thought that they first one gave you the equation and the second one gave you some figures to plug in.

 

So what have you done so far and what do you not understand?

 

Edited October 15, 201411 yr by studiot

After breaking my neck reading the scrolls you posted i thought that they first one gave you the equation and the second one gave you some figures to plug in.

 

So what have you done so far and what do you not understand?

 

11.jpg22.jpg

 

The thing is i need find the time and in order to get that i need to integrate which I'm unable to do with that equation

Show us what you get directly after separation of variables.

this is hat i get... i've made many attempts on it smh

 

Looking at the end of your working surely

 

 

[math]\int {\frac{{a + bx}}{{cx}}} dx[/math] = [math]\int {\frac{a}{{cx}}dx} [/math] + [math]\int {\frac{{bx}}{{cx}}} dx[/math]

 

Where a, b and c are constants.

 

is a very basic integral

Edited October 16, 201411 yr by studiot

Looking at the end of your working surely

 

 

[math]\int {\frac{{a + bx}}{{cx}}} dx[/math] = [math]\int {\frac{a}{{cx}}dx} [/math] + [math]\int {\frac{{bx}}{{cx}}} dx[/math]

 

 

 

Where a, b and c are constants.

 

is a very basic integral

thanks for the help, i tried solving it in that way and i'm still getting the wrong answer.

 

Heres what I've done/:

My post#6 was meant to stimulate questions about your integration.

 

I don't see a logarithm creeping into your working and there should be.

 

What is the integral of a constant times dx and what is the integral of dx/x ?

 

Note I haven't cheched you separation of variables to see if you got the original fraction correct, fuzzwood already asked you for that and I don't see that either.

Edited October 17, 201411 yr by studiot