I've worked out a rate equation:

 

rate=k'[A]^a

 

the nice and easy bit.

 

Now I have to take the logs of both sides of the equation. The thing I'm confused about is that I have no values, it just wants me to show the equation with the logs of both sides taken, so would that literally be shown just as:

 

ln rate= ln k'[A]^a ?

I'm not sure how to do that or if the answer would be as basic as writing log next to both sides?

What do you know about ln(a^b)?

Is it where: a to the power of x = b?

 

Otherwise I'm afraid I do not.

http://en.wikipedia.org/wiki/List_of_logarithmic_identities#Using_simpler_operations

Thanks, I need to improve my maths skills, a point in the right direction is always good.

Right, would it simply be this:

log rate= log k' + log [A]^a

I'm unsure what to do with [A]^a, if anything at all.

Edited February 16, 201312 yr by Iota

It's slightly confusing that they use a twice

If the expression was

....+ ln ([a]^b)

what would you do to it?

I was thinking it would possibly be this:

 

log rate= log k' + b log([A])

You could look at the experimental data and plot the log of the rate versus the log of the concentration.

Looks like a straight line to me, and physical chemists like straight lines on their graphs.

From the slope of the line you can calculate a.

I'll go do that, thanks for your help.

and physical chemists like straight lines on their graphs.

From the slope of the line you can calculate a.

Nothing more true has ever been posted here.

Indeed, and they are quite fond of taking logs of things.

I suspect that the chocolate log was invented by a slightly muddled physical chemistry professor.