zuriel Posted March 7, 2012 Share Posted March 7, 2012 (edited) Hi everyone, I'm learning NMR at the moment and I understand it relatively well - but I have a problem with this spectrum here and it's been bugging me for so long. Can anyone possibly offer some explanantion to me ? The compound is 2-methylpropan-1-ol : As you can see, there are 4 "types" of proton - the 'OH' the 'CH2' the 'CH' and the two chemically equivalent 'CH3's We'd expect 4 proton resonance signals and this is the case, (see spectrum here) : http://www.sigmaaldr.../FNMR000946.PDF I understand the doublet for the CH3, the triplet for the 'CH2' and 'OH' (if OH coupling occurs) but I don't understand the clear SEPTET for the 'CH' - because I'd expect a nonet! Does anyone have any idea why this might be the case in this spectrum? Could it be something to do with J values? Could there be a spectrum error? Any help would be greatly appreciated with this - it's driving me crazy! lol Edited March 7, 2012 by zuriel Link to comment Share on other sites More sharing options...
hypervalent_iodine Posted March 7, 2012 Share Posted March 7, 2012 If you look closely along the baseline, you'll see that it is a nonet. The peaks are a bit tiny because of how huge the methyl peaks are, but they are definitely there. Link to comment Share on other sites More sharing options...
zuriel Posted March 9, 2012 Author Share Posted March 9, 2012 You're most certainly correct - thanks for the help! Link to comment Share on other sites More sharing options...
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