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All atoms of noble gases have their outermost shells completely filled ...

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All atoms of noble gases have their outermost shells completely filled with electrons.

Anyone have idea?

lol, what exatly is the challenge here? Not every one of them have all full, just enough to be inert.

  • Author

I found both information from the internet.

One says yes , the other says no.

the octet is complete if that`s what you mean.

 

and is the challenge to guess what the challenge is, and if so, I WIN :))

"Helium has 8 electrons now!!!! WOW"

 

Rofl :) Yeah, as MolecularMan said, "just enough to be inert".

LOL, like any rule there`s always the exception :))

 

I was tired, leave me alone! :P

 

anyway Helium does have a full outer shell :)

"I was tired, leave me alone! :P"

 

Being tired is my favourite excuse for being wrong, too. :)

well hey, nobody`s Purfikt! :))

 

but yeah I did make a mistake in not considering helium, and yes I was and still am very tired, no excuse I know, just fact.

 

sorry about that.

outer shells include s and p shells

 

to be full you must have 2 electrons in s, and 6 in p for a total of 8

 

this is why they are 'stable' or inert

 

some only have an s shell, therefore they need only 2 = He

i think that the basic school sentence summary is good enough!

 

"... they all have outer shells"

 

summarises it all quite neatly.

sodium doesn't always have a charge of +1. it can have a neutral charge and chemically can have a -1 anionic charge when mixed with anhydrous liquid ammonia

  • 2 weeks later...

Huh?I thought that helium has only two electrons,not 8(duplet).However,it still got full electron shells because the the s shell only requires two to be full.Btw, sodium does not require an electron to complete its outer shell.It needs 7.(highly unlikely).Therefore,it donates the outer electron.The shell beneath is already an octet.Hence it have an electrovalency of +1(excess of 1 electron)This is its normal electrovalency.it tends to lose the excess electron,

right, helium has 2 electrons. it is the one exception.

 

 

sodium actually requires one electron to complete its outer shell because its outer shell is an s. thats why you dont see Na-7 anions in solution with liquid anhydrous ammonia. it loses its electron because of our lovely equation:

 

X=((0.31(n+1+or-c))/r)+0.50

n=valance electrons

c=formal valance charge on atom. is positive or negative depending on polarity of charge.

r=covalent radius

Yep.Correct.Sodium is hard to form a +7 anion because the orbital created will be at all higher energy level(ie:not stable).Similiarly,helium is monoatomic because the teorically He2 moelcule will have two bonding electrons and two anti bonding electrons at different sigma orbitals,cancelling each other out.A He2 +1 molecule is possible though.Upper obital(up electron)Lower obital(up+down electron)It will be stable molecularly but now electically.(its positive)

There is one more characteristic of the Noble gasses that seems to have not been mentioned. The Noble gasses are that way because not only are their outer shells filled, but they're neutral at the same time. So what you have is happy little atoms who are not very sociable with the rest of the atomic world.

 

My highschool teacher would refer to atoms with their outer shells full as happy. :)

There is one more characteristic of the Noble gasses that seems to have not been mentioned. The Noble gasses are that way because not only are their outer shells filled, but they're neutral at the same time. So what you have is happy little atoms who are not very sociable with the rest of the atomic world.

 

My highschool teacher would refer to atoms with their outer shells full as happy. :)

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