ed84c Posted October 10, 2004 Share Posted October 10, 2004 Can anyone tell me the relationship (formulas?) between light intensity and current in a filament light bulb? Link to comment Share on other sites More sharing options...
5614 Posted October 10, 2004 Share Posted October 10, 2004 relationship = more current = more light intensity (until a limit which is quite high, far higher than a normal household light, but super-super-hyper-mega bright spot lights begin to reach the limit!) dunno bout formulae, however it will depend on the bulb itself, the resistance and other properties of the filament itself. Link to comment Share on other sites More sharing options...
ed84c Posted October 10, 2004 Author Share Posted October 10, 2004 yes i guessed that was the relationshipe :-S Link to comment Share on other sites More sharing options...
cyeokpeng Posted November 11, 2004 Share Posted November 11, 2004 Assuming if the tungsten filament has an ohmic property, Power dissipated = I^2*R where R= resistence of the filament. So as current increses, the intensity also increases by the power square law. Link to comment Share on other sites More sharing options...
swansont Posted November 11, 2004 Share Posted November 11, 2004 Assuming if the tungsten filament has an ohmic property' date=' Power dissipated = I^2*R where R= resistence of the filament. So as current increses, the intensity also increases by the power square law.[/quote'] Yes, but generally the resistance of the filament is temperature-dependent, and it gets very hot. So the overall behavior is much more complicated. Link to comment Share on other sites More sharing options...
YT2095 Posted November 11, 2004 Share Posted November 11, 2004 the only data I have is that a regular incandescent light bulb is only 2% efficient, put in 100w and you`ll get 2W of light, the rest is heat an magnetic forces. Link to comment Share on other sites More sharing options...
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