sysD Posted April 6, 2011 Share Posted April 6, 2011 Hey there, I was just wondering if there is a simple way to find turning point (tan=0) coordinates without using calculus. Link to comment Share on other sites More sharing options...
timo Posted April 7, 2011 Share Posted April 7, 2011 How about plotting the function and looking at the graph? Link to comment Share on other sites More sharing options...
michel123456 Posted April 7, 2011 Share Posted April 7, 2011 Geometry. Link to comment Share on other sites More sharing options...
imatfaal Posted April 7, 2011 Share Posted April 7, 2011 For curves symmetric about the turning point you can split the difference between the two roots or indeed any two points that give same f(x) - that would help for some simple curves 1 Link to comment Share on other sites More sharing options...
sysD Posted April 8, 2011 Author Share Posted April 8, 2011 How about plotting the function and looking at the graph? Umm... sorry. That's kind of time consuming, especially on certain graphs.... Geometry. Sounds promising, any leads? For curves symmetric about the turning point you can split the difference between the two roots or indeed any two points that give same f(x) - that would help for some simple curves This is a good idea. I'll implement it in symmetrical graphs. I wish all of them were that easy Link to comment Share on other sites More sharing options...
ydoaPs Posted April 8, 2011 Share Posted April 8, 2011 Why not just use calculus? Link to comment Share on other sites More sharing options...
ewmon Posted April 8, 2011 Share Posted April 8, 2011 (edited) Use difference tables in Excel. Edited April 8, 2011 by ewmon Link to comment Share on other sites More sharing options...
sysD Posted April 9, 2011 Author Share Posted April 9, 2011 Why not just use calculus? Calculus is awesome and all, but I want to have an ironclad grasp on everything "pre-calculus." Link to comment Share on other sites More sharing options...
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