Egh/c^2≠gh/c^2

 

Also, E²=(mc²)²+(pc)²

 

E=mc² is a special case in which the system being studied is at rest with respect to your chosen reference frame.

 

 

So it isn't that simple. You have to consider momenergy per the equation you give. And one would have to choose the apple at rest just before it begins falling as the frame of reference. So E=mc^2 applies for the apple in that r.f. But where to go from there? To figure this out, do we need Einstein's field equations? This would be way beyond my capabilities. Is there anyone out there who can help?

Edited November 6, 201015 yr by I ME

Einstein understood that the observation, or in a larger/proper context 'potential observation' had to be bounded (i.e. non absolute). This in turn allowed him to pursue the notion that the medium for observation was consistent in all reference frames ©. The implications of this are now well known but poorly understood - as they will always be.

Einstein understood that the observation, or in a larger/proper context 'potential observation' had to be bounded (i.e. non absolute). This in turn allowed him to pursue the notion that the medium for observation was consistent in all reference frames ©. The implications of this are now well known but poorly understood - as they will always be.

 

Huh?

Huh?

 

Complementarity - elaborated in this post:

 

http://www.scienceforums.net/topic/52738-relativity-principle/