Chemist98 Posted March 18, 2008 Share Posted March 18, 2008 C%w/w = msubstance / msubstance + msolvent x 100% What is the formula to solve for msubstance? Link to comment Share on other sites More sharing options...
thedarkshade Posted March 18, 2008 Share Posted March 18, 2008 Could you please be more specific on your question, and than you might get some help. I personally find it hard to understand what you really need in this case!!! Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted March 18, 2008 Share Posted March 18, 2008 He's trying to solve the equation [math]C\% = \frac{ m_{\mbox{substance}} } { m_{\mbox{substance}} + m_{\mbox{solvent}} } \times 100[/math] for msubstance. All it takes is some fancy algebra, or an equation solver on a decent calculator. Link to comment Share on other sites More sharing options...
thedarkshade Posted March 18, 2008 Share Posted March 18, 2008 If you're asking for this [math]m_substance[/math] that is in the equation that Cap'n posted than you just need tot follow simple mathematical steps! Link to comment Share on other sites More sharing options...
Chemist98 Posted March 18, 2008 Author Share Posted March 18, 2008 Would it be: msubstance = C% / msubstance + m solvent x100%? Link to comment Share on other sites More sharing options...
Cap'n Refsmmat Posted March 18, 2008 Share Posted March 18, 2008 You've got an msubstance term on both sides, so you can't really solve for it. Link to comment Share on other sites More sharing options...
Chemist98 Posted March 18, 2008 Author Share Posted March 18, 2008 Sorry my mistake:) Is it msubstance = C% / msolution x100%? Link to comment Share on other sites More sharing options...
thedarkshade Posted March 19, 2008 Share Posted March 19, 2008 It's got to be like this (IMO): [math]C \% =\frac{m_s}{m_s + m_S} \times 100[/math] multiply with the part under the fraction and you get" [math]C \% \times m_s + C\% \times m_S = m_s \times 100[/math] then move m-substances in one side and the others in the other side: [math]C \%\times m_s - m_s \times 100 = -C\%\times m_S[/math] factorize: [math]m_s(C \% - 100) = m_S[/math] divide with what you got next to m-substance and finally: [math]m_s=\frac{m_S}{C \% - 100}[/math] s = substance S=solvent Link to comment Share on other sites More sharing options...
iNow Posted March 19, 2008 Share Posted March 19, 2008 Did you mean this? EDIT: Deleted: TDS corrected the latex coding in his post. Link to comment Share on other sites More sharing options...
thedarkshade Posted March 19, 2008 Share Posted March 19, 2008 thanks iNow, I just couldn't figure it out.... tooo fast:D:D .. but there's c-100 not c+100 Link to comment Share on other sites More sharing options...
iNow Posted March 19, 2008 Share Posted March 19, 2008 thanks iNow, I just couldn't figure it out.... tooo fast:D:D .. but there's c-100 not c+100 Beautiful. Your first one is still not rendering properly though... Just fyi. Cheers. Link to comment Share on other sites More sharing options...
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