Atlantic Posted February 8, 2004 Share Posted February 8, 2004 Sorry, it has been so long since i took math. If you have a value (lets say 8000) decreasing by 13% every hour (13% of its actual value not the original value). What would be the formula to find out the current value after 5 hours. Its like bonds. You invest money and it keeps increasing in accordance with the current value. thanks in advance. Link to comment Share on other sites More sharing options...
fafalone Posted February 8, 2004 Share Posted February 8, 2004 n=Cekt Link to comment Share on other sites More sharing options...
Atlantic Posted February 8, 2004 Author Share Posted February 8, 2004 what are the variables? Thanks Link to comment Share on other sites More sharing options...
hamzah Posted March 21, 2004 Share Posted March 21, 2004 I not sure what you mean by bonds, but with annual compound interest...to calculate how much you will have after a given number of years it is: (original value) * (increase)^(number of years) 15% increase would be 115/100 = 1.15 an example would be: £1000 in the bank...with a annual compound interest of 10%...how much is in the bank account after 3 years? 1000 * 1.1^3 = £1331 And in reply to your problem: Sorry, it has been so long since i took math.If you have a value (lets say 8000) decreasing by 13% every hour (13% of its actual value not the original value). What would be the formula to find out the current value after 5 hours. it would be: (initial value) * (decrease)^(number of hours) 8000 * (0.87)^5 Link to comment Share on other sites More sharing options...
xXxAuroraxXx Posted April 12, 2004 Share Posted April 12, 2004 y = 8000(1 - .13)^5 y = 8000(.87)^5 y = 8000(.498) y = 3987.86 Im not sure if "y" is the correct variable... If you wanted to see increase y = 8000(1 + .13)^5 I think. Link to comment Share on other sites More sharing options...
Dave Posted April 12, 2004 Share Posted April 12, 2004 That's right. In general, for things like these interest values, you can use the formula: y = x*(interest)^n to calculate the value of x after n iterations of applying interest or whatever to it. Note that this only works for values of n which are in the natural (counting) numbers - it doesn't work for n = 12.32 for example, for that you need faf's equation. Link to comment Share on other sites More sharing options...
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