andie Posted January 14, 2007 Share Posted January 14, 2007 so i have this lab question to tackle and i am not too sure about the answer. I was wondering what the products are of the reaction: add water to a stest tube then add KMnO4 then add sulfuric acid MIX ALL TOGETHER and then add KI. how do i know what the products are and if there is a precipitate. my observations of this reaction were that the solutions are all clear and colourless then once mixed without the KI they r yellow. once the KI is added the solution turns and orangey brown colour. PLEASE HELP!!! Link to comment Share on other sites More sharing options...
Borek Posted January 17, 2007 Share Posted January 17, 2007 Do I read you correctly - KMnO4 solution is colorless? Borek -- General Chemistry Software www.pH-meter.info/pH-electrode Link to comment Share on other sites More sharing options...
Asian Posted January 18, 2007 Share Posted January 18, 2007 if its a double replacement a precipitate would be formed. u need to use the solutbility rules in order to tell you which one is the solid. Link to comment Share on other sites More sharing options...
woelen Posted January 18, 2007 Share Posted January 18, 2007 You will end up with a precipitate, or with a brown clear solution, depending on how much KI is used (assuming that there is more than sufficient acid added). Andie, please think about this yourself and show that you have put some effort in the problem. This is not http://www.spoonfeeding.net . There are many knowledgeable people over here, and they are willing to help you, but we may also expect some input from you. Link to comment Share on other sites More sharing options...
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