phyti Posted June 14, 2006 Share Posted June 14, 2006 SR implies (or is interpreted as) the space contraction and time dilation depends on the relative velocity of the two reference frames. B moves at .6 c relative to A. B sees objects of known dimensions passing in the opposite direction appearing contracted to .8 their length. A accelerates to .2 c in the direction opposite of B. The relative speed of separation is now approximately .8 c. This would require the contraction B sees to be approximately .6 c. The objects moving past B do not speed up when A moves. How do you explain this? Link to comment Share on other sites More sharing options...
Callipygous Posted June 14, 2006 Share Posted June 14, 2006 assuming the objects B is passing are "stationary" according to your scenario, B is still moving at .6c compared to them(A's acceleration doesnt change the speeds of B or the stationary objects, or their speed relative to each other), and therefore the contraction doesnt change. B is moving at .8 compared to A, so A might look more contracted. ive never understood anything about relativity, but these are my logical assumptions based on what ive been told. sorry for any inaccuracies. Link to comment Share on other sites More sharing options...
Klaynos Posted June 14, 2006 Share Posted June 14, 2006 Also, not sure I've quite understood your thread I'm a little bit worn out... K frame is stationary to an observer. K'' is moving at 0.8c according to an observer in K' K' is moving at 0.5c accoring to the observer in K The velocity of K'' measured in K' also suffers a transformation it is not simply 0.8c+0.5c... Link to comment Share on other sites More sharing options...
phyti Posted June 16, 2006 Author Share Posted June 16, 2006 When Klaynos listed 3 ref frames it got clearer. That's why someone else looking from a distance sees the things that are right under your nose. Thanks Link to comment Share on other sites More sharing options...
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