[math](4-\frac{4}{4})^4=81[/math]

[math]

(4!-4)*4+\sqrt{4}=82

[/math]

Since no one did 83, I might as well just finish that:

[math]

sin^{-1}(cos4)-(\sqrt{4}+\frac{4}{4})=83

[/math]

And 84, since it is so easy:

[math]

(4!-4)*4+4=84

[/math]

My familiarity with the trigometric functions is non-existant. To be be honest I think this stuff is generally way over my head. I don't think I'd ever of managed to get 83. However, as long as no one minds me stealing a good idea I'll fill a few more in that all use the approach:

 

[math]sin^{-1}(cos4)-(\frac{4}{4})^4=85[/math]

 

[math]sin^{-1}(cos4)+4-\sqrt{4}-\sqrt{4}=86[/math]

 

[math]sin^{-1}(cos4)+(\frac{4}{4})^4=87[/math]

 

Credit to the Thing.

I get some easy ones!

 

[math]4!*4-4-4=88[/math]

 

[math]sin^{-1}(cos4)+\sqrt{4}+\frac{4}{4}=89[/math]

 

[math]4!*4-4-\sqrt{4}=90[/math]

Wow the arcsin(cos) thing is having a great vogue here =). Changing it A BIT and we get:

[math]

cos^{-1}(sin\sqrt{4})+4-\frac{4}{4}=91

[/math]

Same thing.

 

Getting onto 92: I'm trying not to use the above method but 92 is quite easy:

[math]

(4!-2)*4+4=92

[/math]

edit: drat, the thing beat me to it

id like to note that you are all insane. and i bow down before your greatness....

 

ive seen this challange many times in math and science classes and never seen people get past 40. usually only like 20.

 

/bow

a couple more

 

[math]tan^{-1}(\frac{4}{4})+4!+4! = 93[/math]

 

[math](4!*4)-4+\sqrt{4}=94[/math]

 

[math](4!*4)-\frac{4}{4}=95[/math]

Hi, the Thing - in your solution to 92 you used a 2. Ignoring the heresy for a moment could you just change it to a sqrt(4) to maintain the purity of 4 throughout.

 

Yes, I know it is silly.

4!*4+4-4=96

[math]

(4!*4) + \frac{4}{4} =97

[/math]

 

and

 

[math]

sin^{-1}(\frac{4}{4}) + 4 + 4 = 98

[/math]

 

 

this is fun

[math]\frac{4!}{.(4!)}-\frac{4}{4}=99[/math]

Dang, I didn't think it'd make it to triple digits and now it's just 1 anyway

I have compiled a list of solutions which do not use functions or square root signs (most of which my very sloppy C++ algorithm found for me). Help me fill in the gaps without cheating?

 

1 = 4*4/(4*4)
2 = 4/4+4/4
3 = (4+4+4)/4
4 = (4-4)/4+4
5 = 4^(4-4)+4
6 = (4+4)/4+4
7 = 4+4-4/4
8 = 4+4+4-4
9 = 4/4+4+4
10 = (4*4+4!)/4
11 = (4+4!)/4+4
12 = (4-4/4)*4
13 = (4+4!+4!)/4
14 = 4!/4+4+4
15 = 4*4-4/4
16 = 4*4+4-4
17 = 4*4+4/4
18 = (4*4!-4!)/4
19 = 4!-(4+4/4)
20 = (4/4+4)*4
21 = 4!+4/4-4
22 = 4!-(4+4)/4
23 = 4!-4^(4-4)
24 = 4*4+4+4
25 = 4!+(4/4)^4
26 = 4!+4!/4-4
27 = 4!+4-4/4
28 = (4+4)*4-4
29 = 4/4+4!+4
30 = (4*4!+4!)/4
31 = (4+4!)/4+4!
32 = 4^4/(4+4)
33 = (4-.4)/.4+4!
34 = 4!/4+4+4!
35 = (4.4/.4)+4!
36 = (4+4)*4+4
37
38 = 44-4!/4
39 = (4*4-.4)/.4
40 = (4^4/4)-4!
41 = (4*4+.4)/.4
42 = 4!+4!-4!/4
43 = 44-4/4
44 = 4*4+4+4!
45 = (4!/4)!/(4*4)
46 = (4!-4)/.4 - 4
47 = 4!+4!-4/4
48 = (4*4-4)*4
49 = 4!+4!+4/4
50 = (4*4+4)/.4
51
52 = 44+4+4
53
54 = (4!/4)^4/4!
55 = (4!-.4)/.4-4
56 = 4!+4!+4+4
57
58 = (4^4-4!)/4
59 = 4!/.4-4/4
60 = 4*4*4-4
61 = 4!/.4+4/4
62 = (4!+.4+.4)/.4
63 = (4^4-4)/4
64 = 4^(4-4/4)
65 = 4^4+4/4
66 = (4+4!)/.4-4
67
68 = 4*4*4+4
69 = (4+4!-.4)/.4
70 = (4^4+4!)/4
71
72 = (4-4/4)*4!
73
74 = (4+4!)/.4+4
75 = (4!/4+4!)/.4
76 = (4!-4)*4-4
77
78
79
80 = (4*4+4)*4
81 = (4/4-4)^4
82
83 = (4!-.4)/.4+4!
84 = (4!-4)*4+4
85 = (4/.4+4!)/.4
86 = (4-.4)x4!-.4
87
88 = 4^4/4+4!
89
90 = (4!/4)!/(4+4)
91
92 = (4!-4/4)*4
93
94 = (4+4!)/.4 + 4!
95 = 4!*4-4/4
96 = 4!*4+4-4
97 = 4!*4+4/4
98 = (4!+.4)*4+.4
99
100

 

And ducky havoc, that last answer for 99 makes no sense.

Maybe the solution to 99 is kinda cheating .. heres another just in case:

 

[math]sin^{-1}(cos(4!))*(\frac{4+\sqrt{4}}{4})=99[/math]

 

[math](4!*4)+\sqrt{4}+\sqrt{4}=100[/math]

 

[math]cos^{-1}(sin\sqrt{4})+\frac{4!+\sqrt{4}}{\sqrt{4}}=101[/math]

 

Bigmoosie - I think filling in the gaps without using any other functions is going to to very difficult and maybe impossible. The ones that have been left blank arethe ones that were quite tough to do.

Hi' date=' the Thing - in your solution to 92 you used a 2. Ignoring the heresy for a moment could you just change it to a sqrt(4) to maintain the purity of 4 throughout.

 

Yes, I know it is silly.[/quote']

Oh oops. Srry. But for some reason the edit button is unavailable right now, can't do anything about it now. Every1, consider the 2 a root 4.

 

But, continuing:

[math]

4!*4+4+\sqrt{4}=102

[/math]

Edit: Oops, sorry, the LaTeX on the above post didn't show up for me before.

 

 

Man, 103 is a tough one.

Err, Xyph, I think you were a bit late - 4 min later than me to post the answer for 102. Nothing to worry about, happened to me and every1 else here.

Soooo, carrying on for 103:

[math]

sin^{-1}(cos\sqrt{4})+\frac{sin^{-1}(\frac{\sqrt{4}}{4})}{\sqrt{4}}=103

[/math]

Whew, glad that's out of the way.

[math](4!*4)+4+4=104[/math]

[math]

\frac{4!}{.4}+tan^{-1}(\frac{4}{4})=105

[/math]

And

[math]

4*4+sin^{-1}(\frac{4}{4})=106

[/math]

[math]arccos(sin(4!+\sqrt{4}))+\frac{arccos(sin4)}{\sqrt{4}} = 107[/math]

 

These functions are pretty useful.

[math]4*4*4*4 = 256 [/math]

[math']4*4*4*4 = 256 [/math]

isn't multiplying them all together kinda defeet the purpose of tryin really really really really really frikin hard to get the right answer right after another consecutively getting larger by 1 each time?

out of curiosity do u guys use scratch paper to do these and use trial and error?

yes, it does defeat the purpose, i don't know why i did it...guess i just wanted to get a high number. that was very noobly of me.

yes, it does defeat the purpose, i don't know why i did it...guess i just wanted to get a high number. that was very noobly of me.

indeed

 

out of curiosity do u guys use scratch paper to do these and use trial and error?

 

I just guessed and checked things on my calculator... yes, I know I'm a cheater.

 

[math]

cos^{-1}(sin(\sqrt{4})+ ((4 * 4) + 4) = 108

[/math]