Kerrowman Posted January 27, 2023 Share Posted January 27, 2023 Can anyone help me calculate the Gibbs free reaction energy in a Lithium Iron Phosphate battery with the combined equation? LiC6 + FePO4 → C6 + LiFePO4 Since the Lithium ions are acting as intermediaries and are on both sides, I understand that they can be removed from the equation. Since the formation energies of all these molecules are not listed in any tables I can find, I presume I have to work from the components of each molecule, so using the Gibbs formation energies of Li+, C6, Fe+, Fe2+ and PO43-, before I can use the combined equation above? For example to get the ΔG°f (FePO4) do I use the equation: Fe3+ + PO43- → FePO4 and then just add the ΔGof Reactants together, which would be -5 + (-1019) kJ/mol I have found the following formation energies so far: ΔG°(Li+) = -58kJ/mol, ΔG°(C) = 0kJ/mol (standard state?), ΔG°(Fe2+) = -79kJ/mol, ΔG°(Fe3+) = -5kJ/mol and ΔG°(PO43-) = -1019kJ/mol For the combined equation I then need to use ΔG°r = 𝛴 ΔGof Products - 𝛴 ΔGof Reactants, however I am not clear how to get the formation energies of all the components in the first place. Thanks Link to comment Share on other sites More sharing options...
Harry_- Posted February 14, 2023 Share Posted February 14, 2023 Sorry I don't have lots of time to write a reply at the moment I'm working on a lab. However if you can find the redox potentials for the cell you could use: ΔGo= nFE n is the number of moles used in the balanced equation F is faraday's constant of 96500 Cmol-1 E is your cell potential under standard conditions (reduction - oxidation potentials) If you need help ask or there are lots of good online videos on that equation. Regards, Harry Link to comment Share on other sites More sharing options...
StringJunky Posted February 14, 2023 Share Posted February 14, 2023 I'll @Kerrowman as that should send them a note you have responded, if they have notifications enabled.. Link to comment Share on other sites More sharing options...
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