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Neo-Classical Physics, 1: Photon gravity and radius, by: Neptune

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I wanted to share a few Algebraic physics formulas, a couple I created and other established ones, and wanted to get the community's reaction and input. Also if the my ideas get big, I want to call them Neo-Classical Physics.

Incase it isn't obvious the ones I created are the rPhoton and gPhoton formulas. I'd like to ask you to review them with your own inputs of different photon frequencies or wavelengths to find errors of them, if any.

And I forgot to write the E=mc2 formula in  the picture but it will be needed to prove my formulas right or wrong. You'll need it in the m=E/c2 form.

Enjoy.

20201221_133309.jpg

  • Author

F is a constant I like to call Flavio's Constant after my First name

I my equations came from Physics equations that I combined and then simplified.

As for testing I've only solved them mathematically to my knowledge to be real, experimentally it's up for grabs

Does this help you better grasp it? I did the calculations for a visible green frequency photon.

Screenshot (147).png

29 minutes ago, Neptune said:

F is a constant I like to call Flavio's Constant after my First name

That’s bad form in physics. 

F is already Force, such a constant is unnecessary, and you don’t name things after yourself

29 minutes ago, Neptune said:

I my equations came from Physics equations that I combined and then simplified.

What equation for a photon radius depends on G?

 

 

  • Author

You can solve the radius of a gravitational body depending on the gravity of the surface. Of course the gravity of the surface of a photon is the gPhoton equation.

That's what In this picture.

 My photon radius and the approach just mentioned above being equal should leave you doubtless. It's not only for green photons if that's your next question, but if you want to ask me to prove that too I will.

Screenshot (148).png

You are serious, then? I couldn't believe you were serious.

\( F= \frac{G}{c^2} \) has units of (mass)-1x(length)

Energy has units of (mass)x(length)2x(time)-2

So \( \sqrt[4]{F\times E_\text{photon}} \) has dimensions of (length)3/4x(time)-1/2. So that's a non-starter from dimensional analysis alone.

Sorry, I honestly thought you were joking in the Physics section. I immediately removed the neg reps.

39 minutes ago, Neptune said:

You can solve the radius of a gravitational body depending on the gravity of the surface. Of course the gravity of the surface of a photon is the gPhoton equation.

That's what In this picture.

 My photon radius and the approach just mentioned above being equal should leave you doubtless. It's not only for green photons if that's your next question, but if you want to ask me to prove that too I will.

 

The problem isn’t getting from one made-up equation to another, it’s tying the equation to something that’s not.

Speculations rules require that you back up your conjecture. Citing one speculation to backstop another doesn’t do that.

  • Author

If the dimensional analysis of it was why does it still give me G when I do this?

Screenshot (149).png

54 minutes ago, Neptune said:

If the dimensional analysis of it was why does it still give me G when I do this?

 

Easy, because as @swansont told you, you're going around in circles.

\[ \frac{\sqrt{FE_R} \left( \sqrt[4]{FE_R} \right)^2}{\frac{E_R}{c^2}} =  \left( FE_R \right)^{\frac{1}{2}+\frac{2}{4}} \frac{c^2}{E_R} =\]

\[  = Fc^2 = \frac{G}{c^2}c^2 = G \]

You derive guess an equation from your definition. You substitute your definition, so you get to an identity. Doesn't matter that your definition dimensionally has no relevance.

And your \( g_\text{photon} \) has the funny dimensions of (length)3/2(time).1.

Edited by joigus
streamlining LateX

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