#8 The density of the copper sample is unknown. The known values include the initial and final volumes and the density of a vessel.
density = 30 mL
initial volume = 5.0 g
final volume = 40 mL
Volume of sample = final volume - initial volume

Is this correct what I have so far??

16 minutes ago, Rachel Maddiee said:

Is this correct what I have so far??

Is density measured in mL  ?

Is volume measured in g ?

 

Let us try this again

The copper sample sinks to the bottom and does not absorb any water or dissolve. so all the rise in in water level is due to the volume of copper sample.

So volume of copper sample = water level after copper added - water level before copper added  =  ? units?

Mass of copper = 5g (given)

So density of copper sample = mass of copper sample / volume of copper sample    =   ?  units  ??

40 - 30 = 10 units 

 5g/10 = 5 units 

I put units ? for you to put in the correct units.  !!!!!!

5g/10  when did you ever put units as well as the numbers into the formula for calculation ?

density = 5 /10 =  ?    and I did ask you what the units for density are. Hint they are something per something else.

Density is in mL?

g/mL

The density of the copper sample is unknown. The copper sample sinks to the bottom and does not absorb any water or dissolve. so all the rise in water level is due to the volume of copper sample.

So volume of copper sample = water level after copper added - water level before copper added  =  ? units?
40 mL - 30 mL = 10 mL

Mass of copper = 5g (given)

So density of copper sample = mass of copper sample / volume of copper sample    =   ?  units  ??
5g/10mL = 0.5 g/mL

 

Does this work?? In my textbook the units are labeled.

27 minutes ago, Rachel Maddiee said:

5g/10mL = 0.5 g/mL

Yeah that the best way.

 

Did I label everything correctly including steps?

2 hours ago, Rachel Maddiee said:

Did I label everything correctly including steps?

Yes but you should remove these bits from your answer ( in two places)

Quote

=   ?  units  ??