What happens to the points (12, -6) in the functions:

Y=√f(x) + 2 (f and (x) are both square rooted)

y=-1/3f(3(x+2))-4?

What do you mean f and (x) are both square rooted? It's just one thing, isn't it? Isn't f(x) the function f with argument x? Can you ask the question again? I don't find what you're going for to be very clear.

I don't find what you're going for to be very clear.

 

But you found it in 3 minutes, which is probably a Homework Help record. If the OP won't pat you on the back for an ASAP like that, I will.

What happens to the points (12, -6) in the functions:

 

Y=√f(x) + 2 (f and (x) are both square rooted)

 

y=-1/3f(3(x+2))-4?

First, try substituting them into the equation.

X = 12

Y = -6