hey, if anyone is willing, could they please give me a bit of help with this problem, i just can't quite figure it out!

 

Thanks

-Sarah

V=IR The current is going to depend on the voltage, which is given, and the impedance. What is the impedance of the circuit?

I = V/Z , where Z is the impedance?

The inductive reactance (XL) of the coil is 2*pi*f*L

where f and L are 50Hz and and .07 henries respectively

 

The resistor ® and inductor (L) are in series, sooo,

the impedance (Z) equals sqrt of (R squared + XL squared)

the angle equals arc tan of (XL ÷ R)

 

If I recall, from ELI the ICE man, voltage leads current.

thanks douglas

Sarah, at first I was thinking that the resistance and inductance were in parallel, then I decided they were in series, sooooo, you posted the "thanks" while I was editing my post.

oh ok, lol , thats cool

ok i think the main equation to be used is the "General equation for motional emf", however i am not quite sure how to apply it.... anyways this was the design i was thinking of ... (i have decided to make a simple theoretical generator first)...

how would you work out the induced emf in the loop(s) of wire if you spun it around in the magnetic field created by those 2 magnets? (the magnets are held stationary)??

oops posted in wrong thread

The inductive reactance (XL) of the coil is 2*pi*f*L

where f and L are 50Hz and and .07 henries respectively

 

The resistor ® and inductor (L) are in series' date=' sooo,

the impedance (Z) equals sqrt of (R squared + XL squared)

the angle equals arc tan of (XL ÷ R)

 

If I recall, from ELI the ICE man, voltage leads current.[/quote']

 

how does this use voltage? and i don't really see where the amplitude of the current in the coil is being worked out?

oh wait, is Ipeak = Vpeak/XL ??

how does this use voltage? and i don't really see where the amplitude of the current in the coil is being worked out?

Swansont gave you the formula

ok, thanks thanks everyone for your help!