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Endercreeper01

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Posts posted by Endercreeper01

  1. It depends on if you are thinking of light as a wave or a particle. In a vacuum, as a wave, the wave is not a straight line, but as a particle, it would be straight. In a vacuum, there is nothing for it to interact with as a particle. As a particle, it wouldn't be like that because of special relativity. If the path was longer, then c would be greater then 299,792,458 m/s. This s not true because we have made measurements with special relativity and the Lorenz factor. If c was different, then the Lorenz factor would be different in the measurement, and therefore, special relativity (sing the value of c we have measured) would not be 100% accurate, and we would have to use a different c.

  2. 1. I know how to create graphs, but not how to put them on top of each other

    2. It is likely that they are talking about the coefficient of form drag only

    3. it gets changed because the average angle from the angle of attack is cos(90-a). This is because the angle of attack is measured parallel to the velocity, and the angle we use is measured perpendicular to the velocity. Therefore, we use cos(90-a). Because cos(90-x)=sin(x), we can rewrite it as sin(a)

    4. I don't know how

  3. 1. I don't know how to plot them over each other

    3. In this case, it is different. Cf0 is just the Cf it has with no angle of attack. The angle of attack effect goes to both terms because of the distributive property. This is why it is Cf0sin(a)

    2. It must be roughly 0 because there is little intercept at a=180

    4. Then it would be about 1.8. The method I used was fitting parameters and my theory. Because a is measured parallel instead of perpendicular to the velocity, it would be sin(a)

  4. Yes. Plot experimental data, the best correlations in the literature, and your correlation. All on the same plot. You should show us that your predictions lie right on top of the experimental data points.

     

    This would be the very basic requirements -- demonstrating that your idea actually, you know, works. I want you to show us that it works.

    Ok, I will show a plot.

    Let's go back to a previous plot.

    cd-vs-alpha-180deg.jpg

    My theory predicts that Cf=Cf0sin(a) where a is the angle of attack. In this case, Cf0 is about 1.8 because the value of the function at 90 degrees is the form drag it has with no angle of attack, and the sin of 0 is 1, so then you get Cf0. Now, let's make a plot of this equation: Cf=1.8sin(a)

    The 2 graphs are exactly the same, except that the second one uses radiants.

  5. Yep. Those are graphs.

     

    But they don't show how well your correlation works. So, I don't see how in any way it answers what I am asking.

     

    One more time... I am asking for you to present just how well your correlations work. That is, show me just how useful your formulas are.

     

    So, you want a plot of my equation? Or do you want me to present it in another way? I am confused about what exactly you want me to tell you.

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