Asimov Pupil

Ok' date=' I am by no means an intellect in science. I completely suck at it. Actually I did well in geology. Anyway, I was hoping one of you guys can clear up some misconceptions I might have. Please try not to get to technical; I am a Film major, so this stuff isn't my field of expertise...In fact I think it’s my mortal enemy.

 

Ok from what I know, when the big bang occurred matter expanded outwards in all directions. Soon this matter collected and the stars/planets where born. Now today we can look at a star/planet and based on the color the wavelengths emits (blue and red shift) we can determine how old it is.

 

Now am I right so far? With the use of blue and red shift can we determine how old a planet/star is?

 

So if this is so, we can look at a star/planet and determine if it is older or younger than earth. Based on this information could we not pinpoint the approximate location where the big bang occurred? So in a sense we know where the universe began?

 

Thanks,

The Confused Salesman [/quote']

 

 

first the red shift doesnt tell you how old it is. it tells you if it is moving away from you (red) and from that you can calculate how far it is away.

 

this way you can tell where they are going. then reverse the direction of all the galaxies and you get the point where the big bang occured

but the anchor is attached to the ground so isn't the ship with respect to the ground?

that's what i said but i meant using calculus

you could shatter basketballs with liquid Nitrogen.

I wanna try please correct me if i'm wrong.

[math]y=2y+2(tan(x))^3[/math]

[math]\frac{dy}{dx}=2y\frac{dy}{dx}-6((tan(x))^2)sec(x)[/math]

[math]6((tan(x))^2)sec(x)=2y\frac{dy}{dx}-\frac{dy}{dx}[/math]

[math]\frac{6((tan(x))^2)sec(x)}{2y-1}=\frac{dy}{dx}[/math]

am i right so far?

[math](\frac{dy}{dx})'=\frac{-((2y-1)((cos(x))^2)(12(tan(x))((sec(x))^2)-6((tan(x))^2)(2y-1)sin2x+((2y-1)((cos(x))^2)(12(tan(x))(sec(x))^2}{((2y-1)((cos(x))^2)^2}[/math]

uh i think the last part is to long!

[math]log1=0[/math]

therefore [math]0=0[/math]

or am i missing something?

looks right

thx

inverse as in putting it under one as a fraction?

the number 54321 is multiplied by a five digit number(*****). the product is a 10 digit number ending in 12345.

what is the number we are multiplying by?

find what is the astericks

thank you

My dad turned around and said that mars was the first of the external planets.

i though it was the last of the internal but i'm not sure.

at first i thought you meant in the solar system, which I would say Europa which isn't a planet. but the universe by all means!

well the diffraction grating is so small that the wave of light hits the openning and is acts as another source except there are so many that it produces multiple dotswith destructive and constructive interference

yeah

I can see why Hp = 0 would upset you.

 

Isn’t the only question here.

 

Is horsepower a measure of Work?

 

And maybe' date='

 

can you do work without moving?

 

Security guards seem to get paid for it….???

 

[/quote']

 

no [math]W=Fd....................D![/math]

is that the same as

[math]|E|=\frac{V}{d}[/math]

lets say hypotheticaly you could break the chain with water current. It doesn't matter because the ship is not producing power so your ship would just drift. Hp still equals zero!

oh.......yeah what he said.

and another thought is if you calculate the force on the anchor by the water it is not generated by the water therefore you have no force by the ship.

therefore you have no force or distance

so say you got 10 micro couloms to the right of a -2 micro couloms test charge.

is this what you are getting at?

[math]F=\frac{kq1q2}{d^2}[/math]

right?

a chemical reaction can also produce water vapour

and if it is then there is no work done therfore no power and no Horse power

we can measure the force on the anchor but the distance is what matters. Do we measure from the water or the ground the anchor is atached to?

i say its measured from the ground.

but the force is not being exerted over a distance