Asimov Pupil

but the anchor is attached to the ground so isn't the ship with respect to the ground?

that's what i said but i meant using calculus

you could shatter basketballs with liquid Nitrogen.

I wanna try please correct me if i'm wrong. [math]y=2y+2(tan(x))^3[/math] [math]\frac{dy}{dx}=2y\frac{dy}{dx}-6((tan(x))^2)sec(x)[/math] [math]6((tan(x))^2)sec(x)=2y\frac{dy}{dx}-\frac{dy}{dx}[/math] [math]\frac{6((tan(x))^2)sec(x)}{2y-1}=\frac{dy}{dx}[/math] am i right so far? [math](\frac{dy}{dx})'=\frac{-((2y-1)((cos(x))^2)(12(tan(x))((sec(x))^2)-6((tan(x))^2)(2y-1)sin2x+((2y-1)((cos(x))^2)(12(tan(x))(sec(x))^2}{((2y-1)((cos(x))^2)^2}[/math] uh i think the last part is to long!

[math]log1=0[/math] therefore [math]0=0[/math] or am i missing something?

looks right thx

inverse as in putting it under one as a fraction?

the number 54321 is multiplied by a five digit number(*****). the product is a 10 digit number ending in 12345. what is the number we are multiplying by? find what is the astericks

thank you

My dad turned around and said that mars was the first of the external planets. i though it was the last of the internal but i'm not sure.

at first i thought you meant in the solar system, which I would say Europa which isn't a planet. but the universe by all means!

well the diffraction grating is so small that the wave of light hits the openning and is acts as another source except there are so many that it produces multiple dotswith destructive and constructive interference

yeah

is that the same as [math]|E|=\frac{V}{d}[/math]

lets say hypotheticaly you could break the chain with water current. It doesn't matter because the ship is not producing power so your ship would just drift. Hp still equals zero!

oh.......yeah what he said.

and another thought is if you calculate the force on the anchor by the water it is not generated by the water therefore you have no force by the ship. therefore you have no force or distance

so say you got 10 micro couloms to the right of a -2 micro couloms test charge. is this what you are getting at?

[math]F=\frac{kq1q2}{d^2}[/math] right?

a chemical reaction can also produce water vapour

and if it is then there is no work done therfore no power and no Horse power

we can measure the force on the anchor but the distance is what matters. Do we measure from the water or the ground the anchor is atached to? i say its measured from the ground.

but the force is not being exerted over a distance