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ChemSiddiqui

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Everything posted by ChemSiddiqui

  1. hi all, I was just wondering if the d6 ions can have spin-only magnetic moment in a tetrahedral field which gives the value 2.83 BM? I cant see that happeing becuase in tetrahedral field the spin is HIGH, and we have 4 unpaired electron to give 4.90. We dont observe the low spin in which case the spin-only magnetic moment will indeed be 2.83. I am confused, I have got a question which asks why d6 ions in tetrahedral field have the magnetic moment 4.90 BM or 2.83 BM while 4.90 BM or 0 BM in an octahedral field. But it does ask which one of the 4 values are not observed in practice!
  2. HP is well advertised because after a long time a british author has succeeded in attracting foreign audience. I dont know J.K.Rowling in my opinion created a novel which circulated around a pillock who as rightly pointed out here has no sense of real magic, is plain stupid and who just make use of his friends help to look like a hero. I cant see why children are so obsessed by HP; its got a similar plot to LOTR (dark lord rising and a group of people going against him etc), its characters arent that cool and its got a touch of romance which i dont see fits really well in a fantasy novel. I might be biased but LOTR is WAY better than HP.
  3. What is that all, ! now thats hilarious how/why would someone write a novel 1000 pages worth and nothing happens!. is it so or you are being biased?. I dont know i read a bit about this novel on wikipedia and from what i read it will be a very boring novel....no disrespect to bascule's taste. I guess I wont buy it then and no its not your opinion that made my mind up!.
  4. hmmm...ok cool. Can you convince me to buy it(I would want to if its good enough, mind!). I havent read it so want to no if its worth buying! o yea, by the way what the genre?
  5. hmm i think i agree you with you there. But, limiting to the particualr genre that is fantasy/fiction at least you can argue that they are 2 of the most famous english(i.e. by british people) novels. Yes, there came out as a series but I reckon they were a single volume split into many to make money if you take my meaning!
  6. Hey everyone, I wanted to share some thought I had about the 2 of arguable the most famous novels(or fantasy fiction) written in English literature. The Lord of the Rings (J.J.R.Tokein) and Harry potter (J.K.Rowling) and to organise a poll for the readers favourite novel. There are some of the things I couldnt help but notice in harry potter which are very similar to LOTR; 1. The Dark Lord; sauron and voldermort were destroyed a long time ago and are seen coming back in their respective novel . The idea is very similar. 2.Chosen One; Harry Potter is the chosen one in harry potter and frodo is chosen one as a ring-bearer in lotr. again the idea is very similar. 3. The black riders and Dementor; another similarity between the two. 4. Frodo and harry's suffering; both suffer a lot along the way of destroying the evils of dark lord. 5. Gandalf and Dumbledore; Both nice and decent personalities, both wizards of great strength and both very wise. now i am not saying anything that might seem obvious to you by my thread, but you cant deny that from what similarties there are harry potter is not exactly an original novel with original ideas from the author. As for which i would vote to be the best of the 2 novels, it clear Lord of the Rings.
  7. Here a link; http://www.chemguide.co.uk/atoms/bondingmenu.html#top this should answer your questions well enough!
  8. Hey thnx Atheist, that is right. God you dont know how much I had to look for this simple relationship. again thnx mate.
  9. Hi, I am not a physics student so i am struglling with this bit; a phase angle corresponds to how many wavelength? say i have the phase angle of 3Pi/2 how many wavelengths would it be? is there a formula for this ? any help appreciated!
  10. Thnx swansont for your help. rep on the way!
  11. right ok, now here's an other question. calculated the KE of He and SF6 from the equations from my last post at 500K and I get the same value for both. I am confused. SF6 is bigger and heavier molecule so must have a smaller value for rms speed which it has but why the same kinetic energy? I get 1.033 x 10^-20 in both cases. What is wrong here...am I on the right track?!
  12. hi, i just wanted to confirm that in the formula that relates KE with root mean square speed; KE= 1/2 mc^2 m is the mass of something rather than the molar mass? Say we have He(helium) which has the molar mass of 0.004 Kg/mol while its mass,m, is 4!. Slightly confused because in the root mean square speed formula I use the molar mass, M. c = (3RT/M)^1/2 thanx in advance for any help!
  13. pH meter will just tell you the pH of the solution while phenopthlein is an indicator. You can take it from here.
  14. To help you further here is the reaction scheme; Metal + Acid ----------> Corresponding Metal Salt + Hydrogen gas Use the link provided by hermantrude and try to figure out which reaction is feasible.
  15. Theres this one called crystal maker for making crystal structure/lattices of inorgnaic compounds. Here's the link; http://www.crystalmaker.com/ Also for physical chemistry you can always use Microsoft excel for doing your calculation and plotting graphs etc. Originlab is a better software for plotting graphs and things like that.
  16. I think canada, I remember him talking about canadian education system somewhere so i guess thats where he is talking about. But thats stupid cold that is.
  17. Well there you go you are contradicting yourself. You see carbon is electropositive element and wheh an electronegative atom is bonded to it , it takes the electron density away from carbon by iductive effect or mesomeric effect and there is a dipole created. however, the h-bonding can only occur with H atom and with highly electronegative atom such as O, N F etc.
  18. There is ChemDraw where you can draw molecules, mechanisms etc. Then there is maple which isnt exactly chemistry software but you can make use of it for chemistry purposes. I posted a link to this software called acd lab which is sticky at the general chemistry forum.
  19. fair enough, although i couldnt quite understand the explaination,,, i get to scared from long explainations.
  20. agreed. Say, just noticed you made it to 700 posts mark. keep contributing to chemical knoweldege of others and yourself and you will find that you are poster with a code name 007(read your number of posts backwards). licence to kill...wonders what that means for chemistry !
  21. I guess you are right. the value is not that off the literature value so I get i shall celebrate i did the experiment well. I like physical chemisrtry experiment and do well in them but dont ask for inorganic or organic...they are a nightmare. thanks
  22. i agree to the poster who says language of maths is probably the hardest to learn( whoever he was...no offence mate). We are doing quantum mechanics theses days and apparently you have to decribe everything with "mathematical" language. but i thought russian is definately difficult to learn with the weird symbols, cant tell its a statement in russian or a list of symbols arranged in a horizontal line.
  23. ChemSiddiqui

    N204

    Ok I did an experiment to find the dissociation enthalpy of N204 and measured the equillibrium vapour pressure relative to the atmosphere. Plotted the graph of result (plot was ln(K) against 1/T*10^3/K-1) and got a straight line with the negative slope which equals -delta H/R(gas constant). I am getting 53 KJ mol-1 as my enthalpy of dissociation. So i was wondering why is it that becuase from my calculation from entalpies of formation of N2O4 and NO2 from the equation ; N2O4 <-------> 2N02 I get 57.3 KJmol-1. My experimental value isn't that off the theoratical value but i am wondering why it is 4 kJmol-1 short. One reson i can think of is that NO2 used isn't pure because when I cooled it using liquid nitrogen it kinda turned pale blue rather than white. But could there be an error is my measurement? what you folks think! Comments or suggestion appreciated.
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