Dhamnekar Win,odd

There is typographical error in the above question. Please read ' Is [math]Ca^{19+}[/math] one electron atom? '

Was the above question correctly stated and correctly answered? In [math]Ca^{19+}[/math], how many electron shells are there? answer is n=1,2,3,4 Then in ground state how can we found its valence electron in 6th shell or n=6? Is [math]Ca^{19+}[/math] one lectron atom?

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An x-ray photoelectron spectroscopy experiment with an unidentified element, X, displays an emission spectrum with four distinct kinetic energies: [math] 5.9 \times 10^{-17} J, 2.53 \times 10^{-18} J,[/math] [math]2.59 \times 10^{-20} J, 2.67 \times 10^{-20} J [/math] (Assume the incident light has sufficient energy to eject any electron in the atom.) (a)Name all of the possible ground state atoms that could yield this spectrum. (b)Calculate the binding energy of an electron in the 2p orbital of element X if the x-rays used for the spectroscopy experiment had an energy of [math] 2.68 \times 10^{-16} J[/math] (c)Consider both the filled and unfilled orbitals of element X. Determine the number of: (1) total nodes in a 4d orbital (2)angular nodes in the [math]2p_y[/math] orbital (3)degenerate 5p orbitals How to answer all these questions?

How to prove (7.1)? How can we use the following two expansion formulas of CDF of normal distribution to prove (7.1) lemma?

Can I ask here statistics question? If yes, under which forum?

For additional information, refer to the following table:

Answer to d) 1)∆H = 17.4 kJ/mol 2)∆H = 8.7 kJ/mol 3)∆H= 4.35 kJ/mol Answer to e) Mechanism for this reaction is [math]1)N_2 + 2 O_2 \rightarrow 2 NO_2 \Delta H^\circ_f = 66.4 kJ/mol [/math] [math]2) N_2O_4 \rightarrow N_2 + 2 O_2 \Delta H^\circ_f = -9.16 kJ/mol [/math]

I realized my mistake. The answer computed for b) is k=-0.4. But how to answer d, e ,f ,g ,h and i? I am working on all these questions. Any chemistry help from the member of this science(Chemistry) forum will be accepted.

How to answer all these questions? Are these above answers correct? Answers to remaining questions will be provided very soon.

[math]2H_2+C_2H_2 \rightarrow C_2H_6[/math] is first order with respect to [math]H_2[/math] and zero order with respect to ethyne and the rate law is [math]Rate=k[H_2],k=\frac{rate}{[H2]}=\frac{1.0 \times 10^{−4}M/min}{0.1M} =1×10^{−3}min^{−1}[/math]

Now, here is the final correct answer provided to me by one great expert mathematician from UK (United Kingdom). That's it.

Now let us replace ψ by y and solve the aforesaid differential equation. Now we replace y by [math]\psi(t)[/math], we get, [math]\psi(t)= C_2 - \displaystyle\int {\frac{1}{C_1 + t -2 \int {\psi(t)}dt}dt}[/math] Now , how to show that velocity and acceleration of a moving particle along a catenary are equal to the given values in the question?

Example: Find the radial and transverse acceleration of a particle moving in a plane curve in Polar coordinates. How can we use this example to solve our original catenary problem? We know [math] \tan{\psi}=\frac{s}{a}, s=c\cdot \sinh{\frac{X}{c}}, V_0 = c , e^\psi= \cosh{\psi} + \sinh{{\psi}}[/math] I am able to get the magnitude of velocity [math]V = c\cdot e^{\psi=0}=c,V = V_0\cdot e^{\psi}[/math] but i am not getting magnitude of acceleration [math]\|\vec{a}\|= \frac{\sqrt{2}}{c} \cdot c^2 \cdot e^{2\psi} \cdot \cos^2{\psi}[/math]

What is the answer to the above question? Any chemistry help will be accepted. I am working on this question.

[math] s= c \cdot \tan{(\psi)}, \frac{ds}{dt} = c\cdot (\tan^2{(\psi)} + 1)[/math]. Now how to compute [math] \frac{d\vec{r}}{ds}[/math] to find velocity?

s is the arc length of a particle P from a fixed point P0(S=0) on curve C. Velocity is [math] \vec{v}(t)= \frac{d\vec{r}}{ds}\times \frac{ds}{dt}[/math] where r⃗ (t) is the position of particle P at time t. Acceleration is [math] \vec{a}(t) = \frac{d\vec{v}}{dt}= \frac{d^2\vec{r}}{dt^2}[/math]

How to answer this question? Any math help, hint or even a correct answer will be accepted.

Answer to d: 5 moles of Ferrous oxalate FeC2O4 are required to reduce 2 moles of Potassium Permanganate in acidic medium. Answer to e: Redox equation is [math] K_2Cr_2O_7 + 3Cu_2S + 14H^+ \rightarrow 6Cu^{2+} + 3S + 7 H_2O + 2K^+ + 2Cr [/math] From the aforesaid equation, we can say that [math] \frac56 [/math] moles of K2Cr2O7 is required to react completely with 2.5 moles of [math]Cu_2S[/math] in acidic medium.

Hello, Both of these above answers are wrong. So ignore the contents of this post.

Are the following rectified answers to a, b, c correct?