Jump to content

Mixed static EM fluxs?


joshuagolden00

Recommended Posts

PLEASE!
what do the E, M, A's and ponying vectors look like when a permanent magnetic dipole has one half of its body (pole) charged + like "N & +" and the other half "S & -"?
and then importantly whats the other orientation (N-)&(S+) behave like..
(just to make sure im not missing anything;)

and what happens to a dipoles flux when its placed in the center of a large permanent toroidal magnet.. does the A field curl all its flux?


thanks!
Link to comment
Share on other sites

Permanent magnetic and electric dipoles don't interact. B (and H but not M) result from the magnetic dipole, E from the electric one.

 

B as well as E are depicted there

https://en.wikipedia.org/wiki/Dipole

 

The Poynting vector isn't used for static fields because it's not useful. From its formal definition of a vector product of E and H, since the parallel dipoles create E and H fields parallel everywhere, the Poynting vector is zero everywhere here.

 

When you write "dipole" it usually implies that it's insensitive to external influences, so admitting that the toroidal magnet has a permeability of nearly one (almost true for ferrites and rare earth, wrong for AlNiCo) the fields just add. Generally, the flux of one source can't be determined, only the flux of the sum, but here a dipole has no size hence the large magnet puts no flux in it, so we could say that the dipole's flux is unmodified.

Link to comment
Share on other sites

  • 1 month later...

thanks for the response!! love looking deep into things i cant find anywhere.. best data is in multiferroic stuff..

hmm.. every thing u say seems true, except that doesn't change that a charged particle would see them as one, so there is an averaged dynamic that is oddly unspoken of.. and about the giant toroidal magnet and small dipole.. hmmm.. idk man, if the little ones end is in the middle of the big one, then all its say, 'S' flux must navigate all that toroidal flux, becoming 'mostly' toridal.. therefore as it meets the unbent N flux, some sort of deal is made and an average bend is left.. but its obviously much more complex than that.

Edited by joshuagolden00
Link to comment
Share on other sites

every thing u say seems true, except that doesn't change that a charged particle would see them as one, so there is an averaged dynamic that is oddly unspoken of

 

 

E and B are different manifestations of the same force, and in mechanics we learn that the motion of a particle is the result of the net force. So I'm not sure what's odd here.

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.