[math]y=e^{sinx}[/math]

 

find [math]\frac{dy}{dx}[/math]

 

i know it equals [math]e^{sin(x)}cos(x)[/math]

 

very easy question but my teacher did it out in her haed so i want to see the right prosess

[math]y=e^{sinx}[/math]

 

find [math]\frac{dy}{dx}[/math]

 

i know it equals [math]e^{sin(x)}cos(x)[/math]

 

very easy question but my teacher did it out in her haed so i want to see the right prosess

 

d/dx e^U = e^U dU/dx

 

in this case U(x)=sin x' date=' so provided you already know that d/dx(sin x) = cos x, then the answer, in your head will be:

 

cos x e[sup']sin x[/sup]

 

Chain rule.

 

Regards

well e^x differentiated is itself but you bring the power down and differentiate that, thats where the cos(X) comes from

oh

 

thx