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Momentum and Velocity After Collision

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A 3.50 kg ball with a velocity of 10.00 m/s collides with a stationary ball with a mass of 5.00 kg. After the collision, the first ball travels at a 42.6 degree angle from its original path, while the second ball travels at a -26.7 degree angle from the other ball's original path.


1) What is the momentum of each ball after the collision?


2) What is the velocity of each ball after the collision?

  • Author

What work have you done so far?

i have p = 3.50kg x 10.00m/s = 35.00 Ns i have no idea what to do from here

  • Author

How do you apply conservation of momentum?

do you use m1v1i+m2v2i=m1v1f+m2v2f?

do you use m1v1i+m2v2i=m1v1f+m2v2f?

 

 

 

Let's call the target object m2. What is v2i?

 

Also, momentum is a vector, so we can (and will need to) write this equation for both the x and y directions (let's say v1i is in the x direction). What is v1iy?

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