Please excuse [deflection] error.

 

Could you help me with the following.

Using continuous beam theory, constructing BM diagram from points b to c, to calculate the max deflection. I only found a have a single solution, though the BM digram show two points of zero bending. I can provide the solution.

your thoughts.

 

[edit: R_b = 685 N]

Please find revised attachment.

attach1(revised).pdf

Edited April 14, 201510 yr by psyclones

What do you mean by 'continuous beam theory' ?

 

I don't see any sign of the three moment equation and the resulting simultaneous equations in your working pdf.

 

It would also be nice to see the reactions identified and labelled.

Thanks for your post.

 

I can assure you I've used 'three moment equation(s)' (solving three equations simultaneously) to arrive at the given moments at b and c, and reaction at b (reaction b is under the support b).

 

My question is, given the manner in which I've formulated the M(x) equation. Is it correct- given I have fixed unequal (in this case) BM's at points b and c, with a free moment due to dist load?

 

[edit] Using the integration method to solve for angle = 0, to solve for deflection. [edit]

Edited April 14, 201510 yr by psyclones

Here is a good pdf on the 3-moment method for continuous beams like yours.

 

http://people.duke.edu/~hpgavin/cee201/three-moment.pdf

 

and here is a simpler worked hand calculated example.

 

http://www.roymech.co.uk/Useful_Tables/Beams/Continuous_Beams.html

Edited April 15, 201510 yr by studiot