I`m currently studying an extended diploma in engineering and one of my assignment was referred and i have no clue how to correct it and my lecturer is no help at all. Could someone please give me a hand

slip gauge height 25mm using a 200mm sine bar

 

1) if DTI A is 2mm higher than B what is the angle of the component

 

2) if DTI B is 10 mm higher than A what is the angle of the component

here is the actual question sheet with some scruffy working out, sorry

i cant rotate it sorry

I presume you (and your lecturer) know how to use a sine bar, the parts of the question you got wrong stem from the engineer's method of setting up.

 

Slips should be added or removed until the top surface of the workpiece is parallel to the surface table.

This can be done by trial and error or by the following 'quick' method.

 

1) Set up the bar and workpiece so the top surface is approximately parallel.

 

2) Take readings from the dial gauges noting the difference and which end is higher.

 

3) If B is lower than A add slips according to the proportion of the sine bar length to the work length.

 

4) IF A is lower than B remove slips according to the proportion of the sine bar length to the work length.

 

So where A is 2mm higher than B the slips need to be increased by {2 x (200/w)}mm, to set the workpiece parallel to the table. Where w is the worklength.

 

This gives a new slip height from which you can calculate the sine and thus the angle

Edited August 13, 201411 yr by studiot

i don't have any of the equipment, and have not been taught how to use sine bars as of yet, my units this year have mainly been based around design and CAD, health and safety and electrical

So have you got the distance between the dial gauges or the workpiece length?

the work piece length is 200 mm. this was a last resort as i have asked many others and still havent got an answer. i really need some help. the work piece is the sin bar

Edited August 21, 201411 yr by Billzey