wanted90 Posted October 15, 2013 Share Posted October 15, 2013 Hi why in this question we did not convert the unit of temperature to kelvin ? Aluminum has A specific heat of 0.902 J/gm C . How much heat is lost when a piece of aluminum with a mass of 23.984 gm cools from a temperature of 415.0 C to a temperature of 22.0 ? the answer is : Q = m Cp X delta T =23.984 X 0.902 X 22 - 415 = -8500 J Link to comment Share on other sites More sharing options...
swansont Posted October 15, 2013 Share Posted October 15, 2013 What is the relationship between ºC and K? And what happens with that relationship when you take a temperature difference (delta T)? Link to comment Share on other sites More sharing options...
wanted90 Posted October 15, 2013 Author Share Posted October 15, 2013 thanks I got it . Link to comment Share on other sites More sharing options...
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