Acnhduy Posted October 3, 2013 Share Posted October 3, 2013 Hello I'm confused as to how to do this question. 4^x + 6(4^-x) = 5I was thinking of changing 4^x to a variable like 'a' so it would be easier to work with, but 4^-x is not the same so I can't replace that with 'a' as well. Then I though 4^-x = 1/4 ^xSo4^x + 6[(1/4)^x] = 5But i have no idea where I'm going with this and I'm lost.Please help, thanks Link to comment Share on other sites More sharing options...
ewmon Posted October 3, 2013 Share Posted October 3, 2013 I think you're on the right track. 4x + 6∙4–x = 5 You set 4x = a Then you thought 4–x = 1/(4x) Good! That makes 4–x = 1/a, and so, you've simplified that term too. So now you have a +6/a = 5 You don't like this? Go ahead and solve it. It will start to look familiar as you work through it. You will grin, honest. After you solve for a, then solve for x. 1 Link to comment Share on other sites More sharing options...
studiot Posted October 3, 2013 Share Posted October 3, 2013 I would guess this is the culmination of an algebra course as it combines several facts about equations and their solution? How would you normally solve an equation with x in the power? There are some other steps to take to put this equation into a suitable form before you can take this action, you will need to change this equation into a quadratic to solve it, Link to comment Share on other sites More sharing options...
Acnhduy Posted October 4, 2013 Author Share Posted October 4, 2013 Thanks guys, it is a quadratic. I was close! Link to comment Share on other sites More sharing options...
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