Jump to content

how does Klein-Gordon equation admit "spontaneous transitions" ?


Widdekind

Recommended Posts

http://wiki.physics.fsu.edu/wiki/index.php/Klein-Gordon_equation

 

The above website says the KG equation admits "spontaneous transitions from positive-energy particle solutions, to negative-energy anti-particle solutions"...

 

Q1: could someone succinctly show, such a "spontaneous transition" sort of solution ?

 

Q2: i personally perceive, a parallel, between the opposite spins, of particles (left-handed) and antiparticles (right-handed)... and the opposite signs, of their frequencies, from the KG equation, which signs cause the phase-factors of particles to spin left-handed [math]e^{- \imath \omega t}[/math], and the phase-factors of antiparticles to spin right-handed [math]e^{+ \imath \omega t}[/math], around on the complex-plane... is it correct, to interpret the positive and negative energies, of particles and antiparticles, as actually merely positive (LH) and negative (RH) phase-factor frequencies ?

 

Q3: the "density" of antiparticles is conserved, but equals -1 (whereas particles normalize to +1)... so the KGE seemingly states, that antiparticles are "absent missing (but whole) holes" in the Dirac sea... is that not essentially the same, as what the Dirac equation demonstrates ? What does the Dirac equation actually demonstrate, that the KGE does not ?

Link to comment
Share on other sites

http://wiki.physics.fsu.edu/wiki/index.php/Klein-Gordon_equation

 

The above website says the KG equation admits "spontaneous transitions from positive-energy particle solutions, to negative-energy anti-particle solutions"...

 

Q1: could someone succinctly show, such a "spontaneous transition" sort of solution ?

 

Q2: i personally perceive, a parallel, between the opposite spins, of particles (left-handed) and antiparticles (right-handed)... and the opposite signs, of their frequencies, from the KG equation, which signs cause the phase-factors of particles to spin left-handed [math]e^{- \imath \omega t}[/math], and the phase-factors of antiparticles to spin right-handed [math]e^{+ \imath \omega t}[/math], around on the complex-plane... is it correct, to interpret the positive and negative energies, of particles and antiparticles, as actually merely positive (LH) and negative (RH) phase-factor frequencies ?

 

Q3: the "density" of antiparticles is conserved, but equals -1 (whereas particles normalize to +1)... so the KGE seemingly states, that antiparticles are "absent missing (but whole) holes" in the Dirac sea... is that not essentially the same, as what the Dirac equation demonstrates ? What does the Dirac equation actually demonstrate, that the KGE does not ?

 

 

 

Well, to show the negative and positive values of the KG equation, is second order in time and admits the solutions

 

[math]\psi(r,t) = e^{\frac{i(pr - Et)}{\hbar}}[/math]

 

where the sign of the energy is

 

[math]E = \pm c \sqrt{p^2 - Mc^2}[/math]

 

The difference between the Dirac equation and the KG equation, is that the Dirac equation describes heavy fermion particles with spin 1/2 states. The KG equation is an equation used to describe spinless particles. Another large difference is that the Dirac equation is first order in time.

Edited by TrappedLight
Link to comment
Share on other sites

do you not mean "sign of the frequency" (not "energy") ? anti-Fermions' phase frequencies are negative (not necessarily their energies). anti-Fermions also have opposite electric (and weak) charge... is there some sort of close connection, between charge <----> energy / frequency ?

Link to comment
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.