n x 10^th Bohr's orbit contains how many number of waves??

 

 

Thanks

 

 

Bohr orbits are subject to the equation

 

[math]n\lambda [/math] = [math]2\pi {r_n}[/math]

 

n = 1,2,3,4....

 

Where r_n denotes the radius of the orbit which contains n wavelengths.

 

Bohr's theory only had one quantum number, n

 

So if n = 10 the circumference of the orbit circle contains 10 wavelengths.

 

Does this help?

 

gosh why is latex so difficult on this site?

Edited July 6, 201312 yr by studiot

Hi,

 

According to Bohr orbits theory the equation is

 

n(lambda) = 2* pi* r(sub n)

 

 

n -> any natuaral number

 

r (sub n)-> the radius of the orbit which contains n wavelengths.

 

so the ans is n

 

Reference:

 

http://chemistry.tutorvista.com/inorganic-chemistry/bohr-s-model-of-the-atom.html