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finding the gravitational pull of a blackhole

Christian.D walker
in Physics

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The pull is what you'd expect of anything with that mass and your distance from it. If you replaced the sun with an equal mass but with a small enough radius such that it was a black hole, we wouldn't notice any gravitational difference.

The acceleration required to maintain constant "r" value, i.e. the equivalent of the Newtonian "g" value, is given by:

 

[math]a=\frac{GM}{r^2\sqrt{1-2GM/rc^2}}[/math]

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