For the ground state, the electron in the H-atom has an angular

momentum = h , according to the simple Bohr model. Angular

momentum is a vector and hence there will be infinitely many

orbits with the vector pointing in all possible directions. is it true??

pls tell why???

According to bohr , the orbital angular momentum is quantized.First bohr orbital will have h/2pi angular momentum and other orbitals have integral multiples of this value. There are infinite orbitals. Electron can exist only in those orbitals for which the orbital angular momentum is nh/2pi.

In the ground state there will be only one orbital (one electron) 1s^1. In an excited state there are theoretically infinite orbitals (it will keep absorbing energy until it no longer feels a magnetic pull from the nucleus and floats away).

In the bohr model, the electron will travel in a circle around the nucleus like a planet around the sun.

Because the electron happens to occupy a spot in the orbital at π/2 instead of 3π/2 or π/6 does not imply it is in a different orbital even though the uniform circular motion acceleration and velocity vector has changed direction.

Is the earth in a different "orbital" ring because it's on the other side of the sun half the time?

Edited October 21, 201213 yr by pluripotency

Think about it this way: if the orbits are in different orientations, is the angular momentum properly quantized? Is the difference between two states still a multiple of h?