ahmed sobhy Posted December 15, 2011 Share Posted December 15, 2011 Can u help with this problem? A charged particle of mass 1.50 g is moving at a speed of 1.50 3 104 m/s. Suddenly, a uniform magnetic field of magnitude 0.150 mT in a direction perpendicular to the particle's velocity is turned on and then turned off in a time interval of 1.00 s. During this time interval, the magnitude and direction of the velocity of the particle undergo a negligible change, but the particle moves by a distance of 0.150 m in a direction perpendicular r to the velocity. Find the charge on the particle. I know that qvb=ma The only unknown to get q is a. How to get it ? Also I am confused, of how it is mentioned that change of velocity is negligible and there is acceleration ? shouldn't a be zero ? Link to comment Share on other sites More sharing options...
Tres Juicy Posted December 16, 2011 Share Posted December 16, 2011 Smells like homework to me... Link to comment Share on other sites More sharing options...
ahmed sobhy Posted December 16, 2011 Author Share Posted December 16, 2011 studying for the final Link to comment Share on other sites More sharing options...
swansont Posted December 16, 2011 Share Posted December 16, 2011 I can't be sure what the writer of the question intended. My guess would be that the intent is that the change in direction can be ignored in terms of kinematics. IOW, you can simplify this to a 1D kinematics problem; given an acceleration you have a certain displacement, and it's a clumsy way of getting a new and different equation for acceleration into the problem. Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now