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Synthesis of Rare Earth Metals Chloride Solutions (ReCl3)

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Hello,

 

I am currently working out the chemical equations to prepare ReCl3 solutions in order to synthesis NaYF4.

The following equation is used to prepare the chloride solution:

Re2O3 + 6 HCl = 2 ReCl3 + 3 H2O

 

In order to prepare 0.5 mol/L of ReCl3 solution, I divided the equation by 4, then I will add more water to the solution to achieve the required concentration. Going forward with the procedure, I should achieve NaYF4.

 

My question is if I want to synthesis NaYF4:20%Er (this means 80% NaYF4 and 20%NaErF4), should the proportion of metal oxides be 80% Y2O3 and 20% Er2O3?

 

Please help me!

  • Author

There isn't any rhenium at all..."Re" stands for "Rare Earth" :)

 

So have you got any idea about the ratio of metal oxides?

I checked with IUPAC, Re really does stand for rhenium.

http://www.iupac.org/

There's a vague convention about using Ln as a symbol for a general lanthanide.

 

There's also a trend away from calling them rare earths because they are not earths and they are not (generally) all that rare.

 

The question isn't really clear. They may mean 20% m/m or possibly 20% mol/mol.

I guess the two ways to find out are to ask the people to whom you are referring, or to try the experiment.

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