Hello,

 

I was wondering if someone can help on this question..

 

What would be the equation for this curve in the figure below?

 

Thanks,

 

Pars

 

Try looking at trigonometric functions

Try looking at trigonometric functions

 

Couldn't I describe it as a "cubic" curve? There's probably some other Latin word for it, but it looks like a cubic equation where y≤a unless that line is there just to mark the exact integer of a.

Edited October 10, 201114 yr by questionposter

cubic are not asymptotic to values of x - whereas that curve looks as if y will tend toward -ve infinity as x approaches d (and for x=0). ie cubic equations do not have a value of x for which y is not defined but this one does. Shape-wise it does look like a cubic - but the cubic heads off to infinity for both x and y - not just y

Couldn't I describe it as a "cubic" curve?

 

You are going off on a tangent now. Swansont has got the right idea.

You are going off on a tangent now. Swansont has got the right idea.

 

questionposer isn't completely off-base. The graph looks like cotangent, but that has a steeper slope at the zero-crossing, and this graph is flatter. cot^3 looks like a better fit.

questionposer isn't completely off-base. The graph looks like cotangent, but that has a steeper slope at the zero-crossing, and this graph is flatter. cot^3 looks like a better fit.

 

Oh wait, I didn't notice that the dashed line represents an asymptote. If that's the cause, it's definitely not a cubic function, it looks like a tangent function although I can't say that for sure because it's zoomed in so much, so it's still possible it's an inverse function. Although you need 3 sides to make a triangle, so how could one side actually be 0? I guess it's just where math and nature don't match up.

Edited October 13, 201114 yr by questionposter

I don't think the dotted lines are definitely asymptotes - if they were then a and b wouldn't be representing anything.

Hello,

 

 

y=(x-a)^3

 

You can give values to "a" like 2, 2.5, 3, etc. All solutions will satisfy the shape of the curve.