Jump to content
1123581321

Exponent Question ?

Recommended Posts

Would someone be able to solve this equation for me: 3e^-10x = 6

 

i just want to see if my solution is right... thanks.

Share this post


Link to post
Share on other sites

The route to a solution can have many paths . Some take one step where others take three . Some explain one step where others explain three . When you put a calculated value for x into the equation do you get an answer of 6 ?

 

 

Share this post


Link to post
Share on other sites

first thing to do would be simplify it and make it clear to the board where the exponent ends. the next step is fairly easy - but fswd is correct; show us what you got already

Share this post


Link to post
Share on other sites

It is possible to make a mistake and another mistake which then corrects it and you don't know of either . When you manipulate the original equation you will get different equations . Put the final value of x that you calculated at the very end into each of these equations to see if the left hand side equals the right hand side all the way from start to finish .

Share this post


Link to post
Share on other sites

ok, i got: x = ln(2/10)...

 

ok, i got: x = ln(2/10)...

but my answer doesn't give me 6 when subbed back into the equation.

Share this post


Link to post
Share on other sites

x is not equal to ln(2/10)

 

I think you have dropped a negative sign somewhere along the way .

 

You may also be getting the natural log of 10 % of what you should be getting the natural log of .

Edited by Hal.

Share this post


Link to post
Share on other sites
ok, i got: x = ln(2/10)...

but my answer doesn't give me 6 when subbed back into the equation.

Then your answer is wrong.

 

i got: x = ln(2/10)...

Show your entire equation. There's no use in speculating about an equation with "..." in it.

Edited by ewmon

Share this post


Link to post
Share on other sites

Finally , I think you brought the 10 into the denominator of what you want to find the natural log of , when it should be a 1/10 multiplication factor in a product with your natural log .

Share this post


Link to post
Share on other sites

1123581321 - you are not really gonna learn unless you put down your method. the comments from forum members are all correct as far as I can see, but they cannot really help till you are more explicit. maths just doesn't work in leaps - it works in small repeatable and easily understood steps; I would do your equation in 5 steps, even though I know what the answer would be in 1 step.

Share this post


Link to post
Share on other sites

The equation of the form [math]e^{\beta x} = \alpha[/math] have a real solution of [math]x = \frac{log(\alpha)}{\beta}[/math],

Edited by khaled

Share this post


Link to post
Share on other sites

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.