smarine Posted October 28, 2009 Share Posted October 28, 2009 Suppose, there's a shorted coil which has a wire resistance R. Also, current i is flowing through the wire. Then, my book is saying that flux linkage "lamda" satisfies the equation " - i R = d(lamda)/dt " Link to comment Share on other sites More sharing options...
swansont Posted October 28, 2009 Share Posted October 28, 2009 Suppose, there's a shorted coil which has a wire resistance R. Also, current i is flowing through the wire. Then, my book is saying that flux linkage "lamda" satisfies the equation " - i R = d(lamda)/dt " That's the equation for Faraday's law of induction, with the substitution that V = IR, which holds in this circuit. Link to comment Share on other sites More sharing options...
smarine Posted October 29, 2009 Author Share Posted October 29, 2009 But I think that "V = d(lamda)/dt" is Faraday's law of induction, and the sign "- i R" doesn't make sense. Link to comment Share on other sites More sharing options...
swansont Posted October 29, 2009 Share Posted October 29, 2009 V=IR The sign is the convention for the direction of current flow, given a particular change in field Link to comment Share on other sites More sharing options...
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