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limit question..


transgalactic

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It should be 1

Firstly take the logarithm of original expression.

ln([sin(x)]^x)=xln(sinx)=(ln(sinx))/(1/x)

take the derivative of both the denominator and numerator

got

lim(-xcosx)*(x/sinx)=lim(-xcosx)=0 when x approaches to 0.

so the original limit will be 1.

limits.doc

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