Chiron Posted December 8, 2008 Share Posted December 8, 2008 Hi, if somebody can give me some insight into this question, it would be greatly appreciated. A solution of vinegar is divided into 2 equal parts. Water is added to one part, while an equal volume of ethanol is added to the other. Do the two parts have the same pH? Why or Why not? If so, which solution is more acidic and why? So, I realize that there's something to do with pKa and the dissociation of ethanol when it is placed in water. When there's ionization, then, the pH will be adjusted. Am I on the right track? Link to comment Share on other sites More sharing options...
hermanntrude Posted December 8, 2008 Share Posted December 8, 2008 I think you are on the right track. Which solvent (ethanol or water) is more likely to rip a proton (H+) off of acetic acid? Which product is more stable ([ce]CH3CH2OH2+[/ce] or [ce]H3O+[/ce])? Link to comment Share on other sites More sharing options...
macscigirl Posted December 11, 2008 Share Posted December 11, 2008 You're on the right track Link to comment Share on other sites More sharing options...
Recommended Posts
Create an account or sign in to comment
You need to be a member in order to leave a comment
Create an account
Sign up for a new account in our community. It's easy!
Register a new accountSign in
Already have an account? Sign in here.
Sign In Now