You come from a family of 6 children consisting of 3 boys and 3 girls. You plan on having 6 children. Assuming you do that what is the probability that you will also have 3 girls and 3 boys.

Since you put this in Genetics and not math, I'll assume this is not homework.

 

You come from a family of 6 children consisting of 3 boys and 3 girls.

This has nothing to do with future results.

 

Assuming the chances of having a boy or girl are equal, the odds of having a total of 3 of each is about 31%.

 

If you want an explanation, you will have to convince me that this is not homework.

Edited October 30, 200817 yr by NeonBlack
fixing quote

There is a homework help forum, and people are more likely to help when you don't insult them by insinuating that they are too dumb to tell a homework question when they see one. We are willing to help you understand, but we are not here to spoon-feed you answers.

 

Here's the equation you want. Ask if you do not understand it.

[math]Probability = p^iq^{n-i}\frac{n!}{i!(n-i)!}[/math]

where

p is the probability of the first result,

q is the probability of the second result,

i is the quantity of the first result,

(n-i) is the quantity of the second result

What were the two kinds of probibility.

Wasnt one logical and the othere realistic.